=Paper= {{Paper |id=Vol-1730/p07 |storemode=property |title=Crank-Nicolson Scheme for Space Fractional Heat Conduction Equation with Mixed Boundary Condition |pdfUrl=https://ceur-ws.org/Vol-1730/p07.pdf |volume=Vol-1730 |authors=Rafał Brociek |dblpUrl=https://dblp.org/rec/conf/system/Brociek16 }} ==Crank-Nicolson Scheme for Space Fractional Heat Conduction Equation with Mixed Boundary Condition== https://ceur-ws.org/Vol-1730/p07.pdf
   Crank-Nicolson Scheme for Space Fractional Heat
      Conduction Equation with Mixed Boundary
                     Condition

                                                          Rafał Brociek
                                                     Institute of Mathematics
                                                Silesian University of Technology
                                              Kaszubska 23, 44-100 Gliwice, Poland
                                                   Email: rafal.brociek@polsl.pl

   Abstract—This paper presents Crank-Nicolson scheme for               numerical solution of space fractional diffusion equation with
space fractional heat conduction equation, formulated with              boundary condition of the first kind, and in paper [12] au-
Riemann-Liouville fractional derivative. Dirichlet and Robin            thors presents finite difference method for two-dimensional
boundary condition will be considered. To illustrate the accu-          fractional dispersion equation. In both papers, as the fractional
racy of described method some computational examples will be            derivative, the Riemann-Liouville derivative was used.
presented as well.
                                                                            In this paper we present numerical solution of space frac-
                       I.   I NTRODUCTION                               tional heat conduction equation. To the equation the Dirichlet
                                                                        and Robin boundary condition was added. In order to solve the
    In recent years the applications of mathematical models             equation, the Crank-Nicolson scheme was used. To illustrate
using the fractional order derivatives are very popular in              the accuracy of described method some computational exam-
technical science. Different types of phenomena in physics,             ples will be presented as well. The aim to achieve numerical
biology, viscoelasticity, heat transfer, electrical engineering,        solution of considered model is application it to solve inverse
control theory, fluid and continuum mechanics can be modeled            problems. Numerical solution of described model is called
by using the fractional order derivatives [6], [23], [10],              solution of direct problem. In the process of solving inverse
[19], [33]. For example in paper [20] mathematical models of            problem, it is required to solve the direct problem many times.
supercapacitors are considered. Authors investigated models             More about inverse problems of fractional order can be found
based on electrical circuits in the form of RC ladder networks.         in papers [2], [3], [4], [5]. In these papers, swarm optimization
These models are described using fractional order differential          algorithms are introduced. More about intelligent algorithms
equations. Often we are not able to solve these models in               and its application can be found in [24], [25], [26], [27], [28].
an analytical way, so it is important to develop approximate
methods of solving differential equations of fractional order.
    Murio in paper [21] presents the implicit finite differ-                       II.     F ORMULATION OF THE P ROBLEM
ence approximation for the time fractional diffusion equations
                                                                           We discuss the following space fractional heat conduction
with homogeneous Dirichlet boundary conditions, formulated
                                                                        equation
by Caputo derivative. In paper [1], implicit finite difference
method was used to solve time fractional heat conduction equa-                           ∂u(x, t)        ∂ α u(x, t)
tion with Neumann and Robin boundary conditions. In these                          c%             = λ(x)             + g(x, t),        (1)
case also, the Caputo derivative was used. In paper [30] authors                           ∂t               ∂xα
describes approximated solution of the fractional equation with         defined in area D = {(x, t) : x ∈ [a, b], t ∈ [0, T )}, where
Dirichlet and Neumann boundary conditions.                              λ(x) is thermal conductivity coefficient, c and % denote the
    Paper [7] describes numerical method for diffusion equa-            specific heat and density. We assume that λ(x) > 0 and α ∈
tion with Dirichlet boundary conditions. To discretization              (1, 2]. The initial condition is also posed
fractional derivative authors used finite difference method
and Kansa method. Paper [11] presents numerical solution                                  u(x, 0) = f (x),     x ∈ [a, b],             (2)
of model describe by fractional differential equation with
space fractional derivative and Dirichlet boundary conditions.          as well as the homogeneous Dirichlet and Robin boundary
Fractional derivative used in this model was Riemann-Liouville          conditions
derivative. Authors used finite volume method.
                                                                                  u(a, t) = q(t),                       t ∈ [0, T ),   (3)
    Also Meerschaert and Tadjeran dealt with fractional dif-                     ∂u(b, t)
ferential equations [13], [12], [14], [35]. Paper [35] describes           −λ(x)          = h(t)(u(b, t) − u∞ ),        t ∈ [0, T ),   (4)
                                                                                   ∂x
  Copyright c 2016 held by the author.                                  where h describes the heat transfer coefficient and u∞ is the
                                                                        ambient temperature.

                                                                   41
    Fractional derivative with respect to space, which occurs in
equation (1), will be the Riemann-Liouville fractional deriva-                                                               1

tive [23], [8] determined as follows                                    (IN −1 −A1 )U k+1 = (IN −1 +A2 )U k +Gk+ 2 ∆t, k = 0, 1, 2, . . . ,
                                                                                                                               (11)
                                Zx
  ∂ α u(x, t)       1      ∂n                                           where
              =                    u(s, t)(x − s)n−1−α ds, (5)
      ∂tα       Γ(n − α) ∂xn
                                 a
                                                                                         U k = [U1k , U2k , . . . , UN
                                                                                                                     k     T
                                                                                                                       −1 ] ,
where α ∈ (n − 1, n] and Γ(·) is the Gamma function [34]. In
case of α ∈ (1, 2), the equation (1) describes super-diffusive                                       h g k+ 12 ∆t          k+ 1
process [15], [16], and for α = 2, we get the classical heat                          k+ 12                                  g 2 ∆t
                                                                                    G         ∆t =      1
                                                                                                                    , . . . , N −2 ,
conduction equation.                                                                                        c%                  c%
                                                                          k+ 21
                III.   N UMERICAL S OLUTION                              gN −1 ∆t λN −1 ∆tu∞   ∆xhk        ∆xhk+1 i
                                                                                 +                     +             ,
                                                                            c%     2(∆x)α    λN + ∆xhk   λN + ∆xhk+1
    In this section we describe numerical solution of equation
(1) using the finite difference method. Let N, M ∈ N be
                                                                        IN −1 is the identity matrix of size N −1×N −1, and matrices
the size of grid in space and time, respectively. We denote
                                                                        A1 and A2 are defined as follows
grid steps ∆x = (b−a)N    and ∆t = T /M . Therefore, we get
following grid
                                                                        i = 1, 2, . . . , N − 1, j = 1, 2, . . . , N − 1,
                                                                                λ ∆t
                                                                               2c%(∆x)α ωα,i−j+1
                                                                                         i
                                                                                                                          j ≤ i − 1,
  S = (xi , tk ), xi = i ∆x, tk = k ∆t, i = 0, 1, . . . , N,                   
                                                             (6)
                                                                               
                                                                                λi ∆t ω
                                                                               
                                                                                                                          j = i ∧ i 6= N − 1,
                   k = 0, 1, 2, . . . , M .                                    
                                                                                2c%(∆x)
                                                                               
                                                                                             α α,1
                                                                               
                                                                                        λi ∆t             λN
                                                                        a1ij =      2c%(∆x)α (ωα,1 + λN +∆xhk+1 )         j = i = N − 1,
We assume the following notation λi = λ(xi ), gik =                            
                                                                               
g(xi , tk ), fi = f (xi ), hk = h(tk ). Values of approximate                           λi ∆t
                                                                                    2c%(∆x)α ωα,0                         j = i + 1,
                                                                               
                                                                               
                                                                               
function in points (xi , tk ), we denoted by Uik .
                                                                               
                                                                               
                                                                               
                                                                                0                                        j > i + 1,
                                                                               
                                                                               
    In order to approximate fractional derivative (5), we used
right-shifted Grünwald formula [17]
                                                                                λ ∆t
                                                                               
                                                                                2c%(∆x)α ωα,i−j+1
                                                                                    i
                                                                                                                            j ≤ i − 1,
 α                               N                                             
∂ u(x, t)     1         1    Γ(j − α)
                                                                               
                                 X                                                λi ∆t
          =        lim α              u(x−(j −1)r, t),
                                                                               
                                                                                        α ωα,1                             j = i ∧ i 6= N − 1,
                                                                                2c%(∆x)
    α
                                                                               
  ∂x        Γ(−α) N →∞ r j=0 Γ(j + 1)                                          
                                                  (7)                   a2ij =     λi ∆t             λN
                                                                                 2c%(∆x)α (ωα,1 + λN +∆xhk )                j = i = N − 1,
                                                                               
                                                                               
                                                                               
where N ∈ N and r = x−a                                                         λi ∆t α ωα,0                               j = i + 1,
                     N . We denote
                                                                               
                                                                               
                                                                               
                                                                                2c%(∆x)
                                                                               
                                                                                 0                                          j > i + 1,
                                                                               
                              Γ(j − α)
                   ωα,j =                 .                  (8)
                            Γ(−α)Γ(j + 1)                                  Solving systems of equations defined by (11), we obtain
                                                                        approximate values of temperatures in points of grid (6).
    Discretize the equation (1) and using approximation of
fractional derivative, we get                                            In paper [35] authors presents proof of unconditionally
                                                                     stability of presented method in case of homogeneous Dirichlet
                                                                     boundary condition. Doing similar proof it can be proven that
Uik+1 − Uik      λi
                       i+1
                       X
                                  k+1
                                          i+1
                                          X
                                                    k
                                                                    described in this paper method is unconditionally stable.
            =              ωα,j U i−j+1 +     ωα,j Ui−j+1
    ∆t        2c%(∆x)α j=0                j=0                                           IV.    E XPERIMENTAL RESULTS
                                  k+ 1
                                 gi 2                                      In this section we presents numerical examples of described
                             +            .
                                     c%                                 method.
                                                             (9)
                                                                           Example 1: Let consider equation (1), defined in area
   Now, we approximate boundary condition of the third kind,
so we obtain                                                                          D = {(x, t) : x ∈ [0, 1], t ∈ [0, 1]},
                                                                        with following data
                         k         k ∞
                 k   λN UN −1 + ∆xh u
                UN =                   .                   (10)                                 1
                         λN + ∆xhk                                       α = 1.7,     λ(x) =      Γ(2.2)x2.8 ,         c = % = 1, u∞ = 50,
                                                                                                6
  Having regard to both boundary condition, the equation (9)                                                                 0.550901e−t
may be written in matrix form                                                g(x, t) = −(1 + x)x3 e−t ,          h(t) = −                .
                                                                                                                               e−t − 50

                                                                   42
To equation we added an initial condition                                     Figure 2 presents exact, approximate solutions and errors
                                                                          for time t = 1.
                     u(x, 0) = x3 ,     x ∈ [0, 1].                       a)                                                              b)
                                                                                  0.006
                                                                                                                                                     0.35
                                                                                  0.005
Exact solution of this problem is function                                                                                                           0.30

                                                                                                                                                     0.25
                                                                                  0.004




                                                                                                                                          uH x,1 L
                                                                          error
                                                                                                                                                     0.20
                                                                                  0.003

                                        3 −t                                                                                                         0.15
                           u(x, t) = x e .                                        0.002
                                                                                                                                                     0.10
                                                                                  0.001
                                                                                                                                                     0.05

                                                                                  0.000                                                              0.00
Maximal and average absolute errors will be defined by                                    0.0        0.2      0.4       0.6   0.8   1.0                     0.0    0.2   0.4       0.6   0.8   1.0
                                                                                                                    x                                                          x
formulas
                                                                          Fig. 2. Distribution of errors for approximate solution (a) and approximate
                                                                          solution (points), exact solution (solid line) (b) in time t = 1 (N = M = 100)
                     ∆max = max         |uki − Uik |,                     (example 1)
                               0≤i≤N
                               1≤k≤M
                                                                              Example 2: Let consider again equation (1) with following
                                  N XM
                         1       X                                        data
           ∆avg =                      |uki − Uik |.
                  (N + 1)(M + 1) i=0                                                       1
                                               k=0                        α = 1.9, λ(x) = , c = % = 1, u∞ = 100, a = 1, b = 2,
                                                                                           2
Table I shows errors of approximate solution for different grids.                                                 32.7273 − 32.7273x
                                                                          g(x, t) = −2t(x−1)+0.0525569(t2 −1)                          +
TABLE I.       G RIDS , MAXIMAL ABSOLUTE ERRORS ∆max AND AVERAGE                                                       (x − 1)1.9
                  ABSOLUTE ERRORS ∆avg ( EXAMPLE 1)
                                                                                                     18.1818     15.5455 − 31.0909x + 15.5455x2 
                                                                                                +              +                                  ,
              Grid N × M        ∆max               ∆avg                                             (x − 1)0.9              (x − 1)2.9
                10 × 10     6.24590 · 10−2     1.23295 · 10−2
                            6.20448 · 10−2     1.26218 · 10−2                                          1
                10 × 50                                                                                  (1 − t2 )
                20 × 20     3.09731 · 10−2     5.58958 · 10−3                                   h(t) = 2           .
                50 × 50     1.23473 · 10−2     2.08623 · 10−3                                           99 + t2
               100 × 100    6.16827 · 10−3     1.01756 · 10−3
               100 × 200    6.16490 · 10−3     1.01786 · 10−3
                                                                          and with initial condition
               100 × 300    6.16429 · 10−3     1.01808 · 10−3
               200 × 100    3.08626 · 10−3     5.02667 · 10−4                                                       u(x, 0) = x − 1,                          t ∈ [0, 1].
               300 × 100    2.05917 · 10−3     3.34012 · 10−4
                                                                          Exact solution of this problem is given by function
    With increase in the first dimension N of the grid, a
fixed second dimension M , errors decrease. For example, for
M = 100 and N = 100, 200, 300 absolute errors not exceed                                                                u(x, t) = (x − 1)(1 − t2 ).
6.17 · 10−3 , 3.09 · 10−3 , 2.06 · 10−3 . Increasing the dimension
of the grid with respect to time for a fixed dimension N                  Table II presents errors of approximate solution for different
insignificantly impact on errors of approximate solution.                 grids.
    Distribution of errors in points of the grid is presented on                           TABLE II.            G RIDS , MAXIMAL ABSOLUTE ERRORS ∆max AND
figure 1.                                                                                                  AVERAGE ABSOLUTE ERRORS ∆avg ( EXAMPLE 2)

                                                                                                           Grid N × M             ∆max                                ∆avg
                                                                                                             10 × 10          7.14165 · 10−4                      4.40379 · 10−4
                                                                                                             10 × 50          6.25414 · 10−4                      3.82786 · 10−4
                                                                                                             20 × 20          4.16933 · 10−4                      2.54149 · 10−4
                                                                                                             50 × 50          2.11043 · 10−4                      1.22171 · 10−4
                                                                                                            100 × 100         1.2352 · 10−4                       6.88743 · 10−5
                                                                                                            100 × 200         1.23129 · 10−4                      6.84358 · 10−5
                                                                                                            100 × 300         1.23059 · 10−4                      6.83813 · 10−5
                                                                                                            200 × 100         7.64731 · 10−5                      3.8691 · 10−5
                                                                                                            300 × 100         5.90598 · 10−5                      2.74809 · 10−5


                                                                              Similarly as in example 1, reducing the grid step ∆x results
                                                                          in a significant reduction in average errors δavg and maximum
                                                                          errors ∆max of approximate solution. Also, the density of
                                                                          the grid in the time domain results in a slight decrease in
                                                                          errors. Distribution of errors in the area of D, for example 2
                                                                          is presented in the figure 3.
                                                                              We also present distribution of errors for approximate
                                                                          solution in time t = 1 (figure 4).
Fig. 1.   Distribution of errors (N = M = 100) (example 1)                                Example 3: Now, we take the following data

                                                                     43
                                                                                                                                                                 V.    C ONCLUSION
                                                                                                                                         In this paper numerical solution of space heat conduction
                                                                                                                                     equation is presented. To the equation Robin and Neumann
                                                                                                                                     boundary conditions were added. Author used Crank-Nicolson
                                                                                                                                     scheme, and right-shifted Grünwald formula for approximation
                                                                                                                                     fractional Riemann-Liouville derivative. To illustrate the accu-
                                                                                                                                     racy of presented method three examples are presented. In each
                                                                                                                                     example results are good. With an increase in the density of
                                                                                                                                     the grid, errors of approximate solution decreases.

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