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<article xmlns:xlink="http://www.w3.org/1999/xlink">
  <front>
    <journal-meta />
    <article-meta>
      <title-group>
        <article-title>On the development of Steffensen's method and applications to Hammerstein equations</article-title>
      </title-group>
      <contrib-group>
        <contrib contrib-type="author">
          <string-name>1 - Ural Federal University (Yekaterinburg, Russia)</string-name>
          <xref ref-type="aff" rid="aff0">0</xref>
        </contrib>
        <aff id="aff0">
          <label>0</label>
          <institution>2 - Krasovskii Institute of Mathematics and Mechanics</institution>
          ,
          <addr-line>Yekaterinburg</addr-line>
          ,
          <country country="RU">Russia</country>
        </aff>
      </contrib-group>
      <fpage>334</fpage>
      <lpage>341</lpage>
      <abstract>
        <p>We construct an analog of Steffensen's method for solving nonlinear operator equations. Proposed method is a kind of two stage iterative process. We study the order of convergence of the method. It is shown that the proposed analog of Stefensen's method, which does not use derivatives, has higher order of convergency then Newton method, other generalizations of chord method or other known modifications of Steffensen's method. Results of numerical experiments with Hammerstein equation are presented.</p>
      </abstract>
    </article-meta>
  </front>
  <body>
    <sec id="sec-1">
      <title>Introduction</title>
      <p>where</p>
      <p>is a mapping from X to X:</p>
      <p>We construct an analog of Steffensen’s method for solving the operator equation (1) as follows
x~(k+1) = x(k)
x(k) = x~(k)</p>
      <p>hF
hF
x~(k);
x~(k)
1. for each fixed x0; x00 2 X operator F (x0; x00) is such that F (x0; x00)(x0
2. if the Frechet derivative F 0(x) exists then F (x; x) = F 0(x):
Note, that functional F (x;0 x00) is obviously nonlinear with respect to x0; x00: Definition 1 does not defines a
unique operator F (x0; x00); indeed the first divided difference could be specified in a numerous of ways. One of
such specification is given in</p>
      <p>
        Statement 1.[10] If there exists a continuous derivative 0(x) in the Gateau sense on the interval [x0; x00];
then we can define the first divided difference (x0; x00) as a Riemann’s abstract integral1 [11]:
(
        <xref ref-type="bibr" rid="ref1">2</xref>
        )
(
        <xref ref-type="bibr" rid="ref2">3</xref>
        )
(
        <xref ref-type="bibr" rid="ref3">4</xref>
        )
(
        <xref ref-type="bibr" rid="ref4">5</xref>
        )
(
        <xref ref-type="bibr" rid="ref5">6</xref>
        )
here M2 is the maximum of the norm of the second derivative max k 00( )k;
where M1 is the maximum of the norm of the Gateau derivative 0 on the segment [x0; x00]:
Definition 2[9] For the operator (x) and each fixed x0; x00; x000 2 X the second divided difference
(x0; x00; x000) is a bilinear operator from the space X to the space (X ! Y ) ; that is (x0; x00; x000) 2 X !
(X ! Y ) ; such that
Using (
        <xref ref-type="bibr" rid="ref4">5</xref>
        ), one can get the following estimate:
      </p>
    </sec>
    <sec id="sec-2">
      <title>Study of convergence</title>
      <p>Let F (x) be a continues, we also assume that the operator of the first divided difference is invertible, i.e. in the
domain of our interest there exist [F (x0; x00)] 1 = [E (x0; x00)] 1:</p>
      <p>Theorem 1 (proof could be found in [14]). Let the following conditions hold:</p>
      <p>X such that for each x0; x00; x000 2
the following three estimations hold</p>
      <p>
        6 ;
2. there exists an open domain
(a) [F (x0; x00)] 1
= [E
Then a) all elements of the sequence x~(k) ; defined by the method (
        <xref ref-type="bibr" rid="ref1">2</xref>
        ) which starts from the certain x~(0), lie in
the ball (
        <xref ref-type="bibr" rid="ref6">7</xref>
        ), b) the sequence x~(k)
      </p>
      <p>
        has a limit x~ in the ball (
        <xref ref-type="bibr" rid="ref6">7</xref>
        ), and c) the estimation takes place
x~
x~(k)
6
      </p>
      <p>C1
C2BKM</p>
      <p>Sk</p>
      <p>(k = 0; 1; 2; : : : ):
x
x~(0)</p>
      <p>
        6 R;
X1 h2n :
n=k
x
x~(0)
6 ;
(
        <xref ref-type="bibr" rid="ref6">7</xref>
        )
(
        <xref ref-type="bibr" rid="ref7">8</xref>
        )
Theorem 2. Assume that
1. equation (1) has a solution in the ball
(a) [F (x0; x00)] 1
= [E
(x0; x00)] 1
      </p>
      <p>6 B;
(b) k (x0; x00)k 6 M ;
(c) k (x0; x00)
(x00; x000)k 6 K kx0
2. for each x0; x00; x000 from the ball x
x~(0)</p>
      <p>
        6 (1 + ) the following three estimations hold
= maxfl2 2; M g; where l = p2CBKM; C is a constant;
Then a) the solution x~ of equation (1) is unique in the ball (
        <xref ref-type="bibr" rid="ref7">8</xref>
        ), b) sequence x~(k) ; defined by the method (
        <xref ref-type="bibr" rid="ref1">2</xref>
        ),
converges to x~ with the third order, i.e. the following estimation of the convergence rate holds
x~
x~(k)
6 1 (l )3
l
k
(k = 0; 1; 2; : : : ):
      </p>
      <p>
        Theorem 2 shows that under natural conditions, the generalized method (
        <xref ref-type="bibr" rid="ref1">2</xref>
        ), that does not use the derivatives,
has a third order of convergence, that is, greater than Newton’s method or generalizations of the secant or
Steffensen method. Theorems 1 and 2 impose less stringent conditions on the operator of the first divided
difference than, e.g., in the papers [7, 15, 16] where some generalizations of the Steffensen’s method were studied.
Moreover, there are no theorems of convergence with order in [7, 15, 16] for the case of operator equations. The
The equation (
        <xref ref-type="bibr" rid="ref8">9</xref>
        ) could also be considered as a special case of the equation (1) where
Let X = C [a; b] ; the functions g(t); K(t; s); f (s; x) are such that the conditions of theorem 2 are satisfied.
      </p>
      <p>The operator of the first divided difference F (x1; x2) is given by</p>
      <p>F (x1; x2) h = h(t)</p>
      <p>
        K(t; s)
Then using (
        <xref ref-type="bibr" rid="ref9">10</xref>
        ) we can determine that iterative process (
        <xref ref-type="bibr" rid="ref1">2</xref>
        ) for equation (
        <xref ref-type="bibr" rid="ref8">9</xref>
        ) requires at each step solution of a
linear integral equation with kernel K(t; s) k(s) where
k(s) =
f s; x~(k)(s)
f s;
      </p>
      <p>x~(k)(s)
x~(k)(s)
x~(k)(s)</p>
      <p>;
F (x~(k)(t)) = x~(k)(t)
g(t)</p>
      <p>K(t; s)f (s; x~(k)(s))ds;
F (x(k)(t)) = x(k)(t)
g(t)</p>
      <p>
        K(t; s)f (s; x(k)(s))ds:
number of function computations at each iteration step for modifications of the Steffensen method [7] is at least
one more than for a generalized method (
        <xref ref-type="bibr" rid="ref1">2</xref>
        ) that requires three function computations at each iteration step.
      </p>
      <p>
        The formal measure of quality is the efficiency index. Method (
        <xref ref-type="bibr" rid="ref1">2</xref>
        ) has higher efficiency index then classical
Newton’s or Steffensen’s method, and the same as the two-step Steffensen’s modification [15, 16].
      </p>
      <p>Definition 3 The index of the efficiency of the iterative method is the quantity p1= , where p is the order of
convergence of the method, is the number of calculations of the function at each iteration step.
3</p>
    </sec>
    <sec id="sec-3">
      <title>Application to the nonlinear integral equations</title>
      <p>We consider an integral equation of Hammerstein type
and calculations of
and</p>
      <p>b
Z
a</p>
      <p>b
Z</p>
      <p>
        b
Z
a
b
Z
a
The numerical solution of the integral equation (
        <xref ref-type="bibr" rid="ref8">9</xref>
        ) raises a number of problems, for example, difficulties connected
with an exact calculation of the integral in (
        <xref ref-type="bibr" rid="ref11">12</xref>
        ) and (
        <xref ref-type="bibr" rid="ref12">13</xref>
        ) and difficulties connected with solution of linear integral
equation. Therefore, we approximate integrals in (
        <xref ref-type="bibr" rid="ref11">12</xref>
        ) and (
        <xref ref-type="bibr" rid="ref12">13</xref>
        ) by quadrature formulas and replace a kernel by
degradate one. Let
      </p>
      <p>
        n(k)
K(t; s) = X
i=0
i(k)(t) i(k)(s) (t; s) 2 [a; b]
[a; b] ;
be a degenerate kernel close to K(t; s); and its approximation accuracy may vary depending on the number of
iteration k: We take the operator ^ k as the operator of the form (
        <xref ref-type="bibr" rid="ref9">10</xref>
        ) in which K(t; s) is replaced by a degenerate
kernel (
        <xref ref-type="bibr" rid="ref13">14</xref>
        ). Further we consider two quadrature formulas:
where the nodes sl 2 [a; b] ; s0l 2 fslg; N 0 6 N: We replace the integral in the discrepancies (
        <xref ref-type="bibr" rid="ref11">12</xref>
        ), (
        <xref ref-type="bibr" rid="ref12">13</xref>
        ) using the
first of the formulas (
        <xref ref-type="bibr" rid="ref14">15</xref>
        ). Then the process (
        <xref ref-type="bibr" rid="ref1">2</xref>
        ) for the equation (
        <xref ref-type="bibr" rid="ref8">9</xref>
        ) will be written so
x~(k+1)(t) = x(k)(t) +
x(k)(t) = x~(k)(t) +
      </p>
      <p>k(t);
k(t);
k(t) =
k(t) =</p>
      <p>n(k)
P^k(t) + X</p>
      <p>
        n(k)
Q^k(t) + X
i=0
i=0
i(k)(t)ci(k);
i(k)(t)di(k);
(
        <xref ref-type="bibr" rid="ref15">16</xref>
        )
(
        <xref ref-type="bibr" rid="ref16">17</xref>
        )
(
        <xref ref-type="bibr" rid="ref17">18</xref>
        )
(
        <xref ref-type="bibr" rid="ref18">19</xref>
        )
(
        <xref ref-type="bibr" rid="ref19">20</xref>
        )
(
        <xref ref-type="bibr" rid="ref20">21</xref>
        )
(22)
(23)
(24)
where
      </p>
      <p>Q^k(t) = x(k)(t)</p>
      <p>P^k(t) = x~(k)(t)
ei(k) =
i(k)(s) k(s)Q^k(s)ds</p>
      <p>N0
X A0l i(k)(s0l) k(s0l)Q^k(s0l) = e^i(k);
l=0
l=0
l=0
N
X AlK(t; sl)f (sl; x(k)(sl))ds;
N
X AlK(t; sl)f (sl; x~(k)(sl))ds;
l=0
l=0
N0
X A0l i(k)(s0l) k(s0l)P^k(s0l) = ^bi(k);
N0</p>
      <p>X A0l i(k)(s0l) k(s0l) j(k)(s0l) = a^i(jk);
g(t)
g(t)
j=0
j=0</p>
      <p>1
Z
0
k = 0; 1; 2; : : : ; the constants ci(k) are found from the linear system
in which
ci(k) =</p>
      <p>
        n(k)
bi(k) + X ai(jk)c(jk); i = 0; 1; : : : ; n(k);
the constants di(k) are found from the linear system
in which ai(jk) are calculated by the formula (
        <xref ref-type="bibr" rid="ref20">21</xref>
        ) and
d(k) =
i
      </p>
      <p>n(k)
ei(k) + X ai(jk)d(jk); i = 0; 1; : : : ; n(k);
bi(k) =</p>
      <p>i(k)(s) k(s)P^k(s)ds
ai(jk) =</p>
      <p>
        i(k)(s) k(s) j(k)(s)ds
k(s) looks similar to (
        <xref ref-type="bibr" rid="ref10">11</xref>
        ). The second quadrature formula (
        <xref ref-type="bibr" rid="ref14">15</xref>
        ) is used to calculate the integrals (
        <xref ref-type="bibr" rid="ref19">20</xref>
        ), (
        <xref ref-type="bibr" rid="ref20">21</xref>
        ) and
(23).
      </p>
      <p>
        The simple fact of the matter is, it is more convenient to implement the process (
        <xref ref-type="bibr" rid="ref15">16</xref>
        ) for grid functions2 of
approximations x~k+1(t) by setting t = ti = si; i = 0; 1; : : : ; N:
      </p>
      <p>Example 1. Let us consider the integral equation in [18]:
x(t) = 1
0:4854t + t2 +
ts arctg x(s)ds;
t 2 [0; 1];
2A typical situation: instead of an exact solution functions we find a table of its approximate values (a skeleton), and then,
if necessary, we make a replacement, for example, by spline interpolation. It is natural that the approximate solution obtained in
this way belongs to a space that is narrower than the original solution space [17].</p>
      <p>1
Z
0</p>
      <p>1
Z
0
here g(t) = 1 0:4854t + t2; K(t; s) = ts; f (s; x(s)) = arctg x(s): The exact solution of equation (24) is
x (t) = 1 + t2:</p>
      <p>Let us verify that the conditions of Theorem 2 are satisfied. The first divided difference for the operator on
the right-hand side of the equation (24) has the form
is satisfied in the whole space C[0; 1]; then according to the definition 2 and statement 2
that is, the condition 2c) is satisfied.</p>
      <p>Since k (x1; x2)k 6 1=2 the following expansion and inequality hold
k[E</p>
      <p>1
(x0; x00)] 1k = X k (x0; x00)kn 6 2;
n=0
that is, the condition 2a) is satisfied.</p>
      <p>
        We solved the equation (24) using the method (
        <xref ref-type="bibr" rid="ref15">16</xref>
        ). In the first series of numerical experiments, we investigated
the influence of the initial approximation x~(0) on the rate of convergence (here it is measured as a number of
iterations required to achieve a given accuracy 10 5).
      </p>
      <p>
        Let us divide the segment [0; 1] uniformly into N = 10 parts and form the time grid ti; i = 0; :::; N: Let us
put N 0 = N: We searched a approximate solution, ie, a grid function x~k(ti): We used the Simpson formulas with
N = N 0 nodes as a quadrature formulas for (
        <xref ref-type="bibr" rid="ref14">15</xref>
        ). The stop criterion was taken as kx~(k+1) x~(k)k &lt; 10 5:
We considered the following initial conditions
1. x~(0)(t)
2. x~(0)(t)
3. x~(0)(t)
4. x~(0)(t) =
      </p>
      <p>
        The results of the numerical experiments for (
        <xref ref-type="bibr" rid="ref15">16</xref>
        ) are presented in the table 1. In the first column, the nodes
of the time grid tk are listed, in the second column the values of the exact solution at the grid nodes x (tk)
are listed. Columns three through six are similar: the differences between the exact x (ti) and the approximate
solution x~k(ti) in the grid nodes are indicated, here the index k corresponds to the iteration number when the
required accuracy has been achieved. In the lower part of the table, the norms of the difference between the exact
x (ti) and the approximate solutions x~k(ti) are given; and the norm-maximum was used.
      </p>
      <p>It is seen from the table that even for nonsmooth initial approximations which oscillates with high frequency
and amplitude the method converges, and it is necessary only one iteration to achieve the required accuracy. For
the initial approximation x~(0)(t) = 20 + 10j sin(5 t)j the experiment also shows good smoothing properties of
the method.</p>
      <p>The results obtained for the initial approximation x~(0) = 1:5 (stop criterion is kx~(k+1) x~(k)k &lt; 10 6) exceed
the results of applying the Steffensen’s method [19] (k = 2) to this equation by the number of iterations, which
in turn is better than Newton’s method [20] (results of comparison of the Steffensen’s method and the Newton’s
method for the equation (24) are given in [19]).</p>
      <p>Example 2. Let us consider the integral equation, see [21]:</p>
      <p>
        The corresponding exact solution of the equation (25) is x(t) = t: We solved the equation (25) using the method
(
        <xref ref-type="bibr" rid="ref15">16</xref>
        ), the initial approximation was taken as follow x~(0) = g(t): The degenerate kernel (
        <xref ref-type="bibr" rid="ref13">14</xref>
        ), which approximates
K(t; s) = ets; was taken as the sum of n(k) terms of the Taylor expansion. As the quadrature formulas (
        <xref ref-type="bibr" rid="ref14">15</xref>
        )
the Simpson’s formulas were used with N = N 0 = 81: Stop criterion was taken as kQ^k(t)k &lt; 10 6: The results
of the numerical approximations (
        <xref ref-type="bibr" rid="ref15">16</xref>
        ) are given for three nodes in the table 2. From table 2 it is seen that the
method (
        <xref ref-type="bibr" rid="ref15">16</xref>
        ) has converged in 3 iterations, while the analog of the Aitken-Steffensen method with a controlled
step [21] converges in 9 iterations.
      </p>
      <p>
        Note that application of the process (
        <xref ref-type="bibr" rid="ref1">2</xref>
        ) to the equation (25) requires at each iteration step to solve a linear
system with N equations, while the iterative process (
        <xref ref-type="bibr" rid="ref15">16</xref>
        ) requires to solve a linear system with n(k) equations.
      </p>
    </sec>
    <sec id="sec-4">
      <title>Acknowledgements References</title>
      <p>This research is supported by Program 02.A03.21.0006 on 27.08.2013.
[1] A. M. Ostrowski. Solution of equations and systems of equations. New York, 1960.</p>
    </sec>
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