<!DOCTYPE article PUBLIC "-//NLM//DTD JATS (Z39.96) Journal Archiving and Interchange DTD v1.0 20120330//EN" "JATS-archivearticle1.dtd">
<article xmlns:xlink="http://www.w3.org/1999/xlink">
  <front>
    <journal-meta />
    <article-meta>
      <title-group>
        <article-title>Problem of Distribution of Goods by Logistics Centers</article-title>
      </title-group>
      <contrib-group>
        <contrib contrib-type="author">
          <string-name>Anatoly Panyukov</string-name>
          <xref ref-type="aff" rid="aff0">0</xref>
        </contrib>
        <contrib contrib-type="author">
          <string-name>Khalid Z. Chaloob</string-name>
          <email>khalid.e@mail.ru</email>
          <xref ref-type="aff" rid="aff0">0</xref>
        </contrib>
        <aff id="aff0">
          <label>0</label>
          <institution>South Ural State University</institution>
          ,
          <addr-line>76 Lenina Ave., 454080, Chelyabinsk</addr-line>
          ,
          <country country="RU">Russia</country>
        </aff>
      </contrib-group>
      <fpage>304</fpage>
      <lpage>314</lpage>
      <abstract>
        <p>E ective logistics management is recognized as a key factor in improving the performance of companies and their competitiveness. The econometric methods used in practice do not provide the means for promptly solving a multitude of emerging problems, in particular for e ective operational management of a network marketing organization. In the paper, algorithms for analyzing and solving the problem of distribution of goods by logistics centers, including decision support system in case of incorrectness of the arising problem are proposed: (1) the method of regularization of the decomposable distribution problem; (2) an e ective algorithm for approximating an indecomposable problem by a decomposable problem. The software implementation of the proposed algorithms is easily encapsulated in the MS O ce system.</p>
      </abstract>
      <kwd-group>
        <kwd>Logistics center</kwd>
        <kwd>Transport problem</kwd>
        <kwd>Operational manage- ment</kwd>
        <kwd>Distribution task</kwd>
        <kwd>Regularization</kwd>
        <kwd>Decomposition</kwd>
        <kwd>Algorithm</kwd>
      </kwd-group>
    </article-meta>
  </front>
  <body>
    <sec id="sec-1">
      <title>-</title>
      <p>A enterprise is a complex and dynamic system actively interacting with the
external environment. Currently, e ective logistics management is recognized as a key
factor in improving the performance of companies and their competitiveness [9,
3]. Budashevsky, and Pastukhova [2] propose constructive comparative analysis
of methods and models for estimating demand used in economics and
marketing and system technology for analyzing and forecasting consumer preferences.
Bayev and Drozin [1] consider questions of the dynamics of consumer demand.
Levin notes [4] that these methods do not provide the means to quickly solve a
lot of emerging problems, in particular for e ective operational management of
the network marketing organization.</p>
      <p>Algorithms for analyzing and solving the problem of the distribution of goods
by logistics centers, including a decision support system in case of illposed arising
Copyright c by the paper's authors. Copying permitted for private and academic purposes.
In: S. Belim et al. (eds.): OPTA-SCL 2018, Omsk, Russia, published at http://ceur-ws.org
problem are proposed in the paper. Software implementation of these algorithms
is easily encapsulated in the MS O ce system [5, 6].</p>
      <p>In the rst section we give a formal statement of the problem and introduce
the main notation used of this paper. In the second section we consider the
decomposable case of a problem reducible to the transport problem with matrix
formulation. In the third section we propose a method for regularizing a
decomposable problem in the case of its illposed formulation. In the fourth section we
propose a method for approximating the problem of the original problem with
a decomposable problem.
2</p>
      <p>Statement of the Problem
The problem of distributing a set I of goods over a set J of logistics centers is
considered. Let xij be the volume of the commodity i 2 I distributed to the
center j 2 J . Let pij be the marginal pro t from the sale of a unit of commodity
i 2 I at the center j 2 J . Let ij be the cost of distribution of a unit of
commodity i 2 I by the center j 2 J . Let di be the e ective demand for the
commodity i 2 I. Let bj be the resource for the maintenance of the center j 2 J .
The formal formulation of the problem consists in nding the distribution of
goods i 2 I at the centers j 2 J , for which the marginal pro t is maximal
all goods are satis ed with the e ective demand
resource constraints have been met for all centres
xo = arg max X X pij xij ;</p>
      <p>
        x2D j2J i2I
X xij = di;
j2J
The problem (
        <xref ref-type="bibr" rid="ref1">1</xref>
        )-(
        <xref ref-type="bibr" rid="ref4">4</xref>
        ) is the known distribution task of linear programming [7,
8]. In general, for this task is not known methods that take into account its
speci city, so to solve it apply universal methods of linear programming. For
large-scale tasks, this approach requires commercial software. In addition, if
problem (
        <xref ref-type="bibr" rid="ref1">1</xref>
        )-(
        <xref ref-type="bibr" rid="ref4">4</xref>
        ) has no solution, the principle of making an acceptable decision
is not clear in this statement.
(
        <xref ref-type="bibr" rid="ref1">1</xref>
        )
(
        <xref ref-type="bibr" rid="ref2">2</xref>
        )
(
        <xref ref-type="bibr" rid="ref3">3</xref>
        )
(
        <xref ref-type="bibr" rid="ref4">4</xref>
        )
      </p>
      <p>
        The Decomposable Case of Task (
        <xref ref-type="bibr" rid="ref1">1</xref>
        )-(
        <xref ref-type="bibr" rid="ref4">4</xref>
        )
For some cases, the parameter ij can be represented as the product
ij =
i
j ; i 2 I; j 2 J
(
        <xref ref-type="bibr" rid="ref5">5</xref>
        )
where i is the resource intensity of the commodity i 2 I in conventional units,
j is the cost of servicing the conventional unit at the center j 2 J . This case of
the problem (
        <xref ref-type="bibr" rid="ref1">1</xref>
        )-(
        <xref ref-type="bibr" rid="ref4">4</xref>
        ) is called as decomposable problem. It is possible decomposable
problem (
        <xref ref-type="bibr" rid="ref1">1</xref>
        )-(
        <xref ref-type="bibr" rid="ref4">4</xref>
        ) reducing to the matrix transportation problem. Indeed, for all
j 2 J we have
      </p>
      <p>X
i2I
,</p>
      <p>X
i2I
i j xij</p>
      <p>X</p>
      <p>
        ,
ixij
here yij = i xij for all i 2 I; j 2 J . Passing to the variables yij =
all i 2 I; j 2 J in problem (
        <xref ref-type="bibr" rid="ref1">1</xref>
        )-(
        <xref ref-type="bibr" rid="ref4">4</xref>
        ) get
bj !
j
      </p>
      <p>X yij
i2I
bj !
j</p>
      <p>;
i xij for
0</p>
      <p>X</p>
      <p>
        X yij =
j2J
di
i
1
A ;
Thus, the problem (
        <xref ref-type="bibr" rid="ref1">1</xref>
        )-(
        <xref ref-type="bibr" rid="ref4">4</xref>
        ) is equivalent to the following one
yo = arg max X X pij yij ;
      </p>
      <p>x2D j2J i2I i
X yij =
j2J
X yij
i2I
yij
0;
di
i
;
bj ;
j</p>
      <p>
        i 2 I
j 2 J ;
The problem (
        <xref ref-type="bibr" rid="ref6">6</xref>
        )-(
        <xref ref-type="bibr" rid="ref9">9</xref>
        ) is open matrix transportation problem [7, 8]. The
encapsulated in the MS O ce system software to solve such problems of large dimension
is known [6].
      </p>
      <p>
        Regularization of Problems (
        <xref ref-type="bibr" rid="ref1">1</xref>
        )-(
        <xref ref-type="bibr" rid="ref4">4</xref>
        ) and (
        <xref ref-type="bibr" rid="ref6">6</xref>
        )-(
        <xref ref-type="bibr" rid="ref9">9</xref>
        )
Problem (
        <xref ref-type="bibr" rid="ref6">6</xref>
        )-(
        <xref ref-type="bibr" rid="ref9">9</xref>
        ) (hence and (
        <xref ref-type="bibr" rid="ref1">1</xref>
        )-(
        <xref ref-type="bibr" rid="ref4">4</xref>
        )) has a solution when demand does not exceed
the supply, i.e.
      </p>
      <p>S =</p>
      <p>X di
i</p>
      <p>
        X bj
j2J j
0:
Otherwise (that is, if S &gt; 0), the problems (
        <xref ref-type="bibr" rid="ref1">1</xref>
        )-(
        <xref ref-type="bibr" rid="ref4">4</xref>
        ) and (
        <xref ref-type="bibr" rid="ref6">6</xref>
        )-(
        <xref ref-type="bibr" rid="ref9">9</xref>
        ) do not have
admissible solutions, and it is required to correct the original problem to nd a
suitable solution. Possible ways to adjust the conditions of these tasks are:
1. To allow the supply of all goods below the e ective demand
2. To develop the infrastructure of all routes in order to e ectively support the
e ective demand
where y0j is the amount of investment (in conventional units) in the
development of the route j 2 J .
      </p>
      <p>Let ki be the allowed fraction of the unsatis ed demand for the commodity i 2 I
(i.e. yi0 kidi). Let p0j be the amount of investment required to expand the
resources of the center j 2 J by one conditional unit.</p>
      <p>Let us consider the corrected problem taking into account the variables and
restrictions introduced in this section.</p>
      <p>yo = arg max X
y2D j2J</p>
      <p>X pij yij
i2I</p>
      <p>i
X yij + yi0 =
j2J
X yij
i2I</p>
      <p>yi0
yij ; yi0; y0j
y0j =
kidi;
0;
di
i
;
bj ;
j</p>
      <p>!
p0j y0j</p>
      <p>
        ;
The problem (
        <xref ref-type="bibr" rid="ref10">10</xref>
        )-(14) is closed matrix transportation problem [7]. The
encapsulated in the MS O ce system software to solve such problems of large dimension
is known [6].
      </p>
      <p>
        Obviously, problem (
        <xref ref-type="bibr" rid="ref10">10</xref>
        )-(14) has an optimal solution. The regularization is
carried out by introducing additional endogenous variables yi0; y0j 0; i 2
I; j 2 J , exogenous variables ki; i 2 I, and constants p0j ; j 2 J .
      </p>
      <p>It is evident from the constructed model that at xed prices maintaining
e ective demand leads to a decrease in marginal pro t. Preservation of marginal
pro t requires an increase in the selling price of goods, which can lead to an
irreversible decrease in demand and a decrease in marginal pro t. Thus, the task
of decision-making in conditions of risk and uncertainty arises. The controlled
parameters in this case are the exogenous variables ki; i 2 I.</p>
      <p>
        Let us use the marginal pro t M and the amount of unmet demand S as
criteria in the decision-making model. It is obvious that all solutions of problem
(
        <xref ref-type="bibr" rid="ref10">10</xref>
        )-(14) are Pareto optimal ones for xed values of the exogenous variables
ki; i 2 I. The problem of choosing speci c values of these variables is di cult
to formalize and requires the participation of the decision-maker (DM).
5
      </p>
      <p>
        Approximation of the Problem (
        <xref ref-type="bibr" rid="ref1">1</xref>
        )-(
        <xref ref-type="bibr" rid="ref4">4</xref>
        ) by the
      </p>
      <p>
        Decomposable Problem
As was noted above, problem (
        <xref ref-type="bibr" rid="ref1">1</xref>
        )-(
        <xref ref-type="bibr" rid="ref4">4</xref>
        ) is decomposable if the equalities (
        <xref ref-type="bibr" rid="ref5">5</xref>
        ) hold.
The value of the parameter ij is interpreted as the cost of distributing a unit
of commodity i 2 I by the center j 2 J , and its value can be determined
using statistical measurements. On the contrary, the parameters f i &gt; 0 : i 2 Ig,
f j &gt; 0 : j 2 J g are interpreted using the term "conventional unit", therefore
their direct statistical measurement is impossible. Therefore, we consider the
equalities (
        <xref ref-type="bibr" rid="ref5">5</xref>
        ) as a system of algebraic equations with unknowns f i &gt; 0 : i 2 Ig,
f j &gt; 0 : j 2 J g. It is clear that for arbitrary values ij the system of equations
(
        <xref ref-type="bibr" rid="ref5">5</xref>
        ) may be inconsistent.
      </p>
      <p>Let us introduce the function</p>
      <p>F ( ; ) =</p>
      <p>
        X
Obviously, inf F = 0 if and only if the system of equations (
        <xref ref-type="bibr" rid="ref5">5</xref>
        ) is consistent.
It follows from the nonnegativity of the function F () that the value of inf F
can be considered as the degree of incompatibility of the system (
        <xref ref-type="bibr" rid="ref5">5</xref>
        ). Function
F (); &gt; 0 is continuous in the neighborhood of any minimum, so the in mum is
reached, and the optimal approximate solution of the system (
        <xref ref-type="bibr" rid="ref5">5</xref>
        ) with a minimal
degree of incompatibility
( o; o) = arg
      </p>
      <p>2
min 4
f j&gt;0: j2Jg i2I; j2J
f i:&gt;0: i2Ig</p>
      <p>X
log
i j
ij
3
5
can be considered.</p>
      <p>It is easy to see that the optimality of the solution ( o; o) implies the
optimality of the solution set D = f( o c; o=c) : c &gt; 0g. We shall assume that
the solution of the approximating problem is
( ;
) = arg
( m;i)n2D k( ; )k1 :
(15)
Note that if ( ; ) 2 D then</p>
      <p>(
=
ak
s maxj2J j</p>
      <p>
        )
maxi2I i
k2I
;
=
k
r maxi2I i
maxj2J j k2J
:
Thus, the correct formulation of the approximating problem is two-level, but for
its solution it is su cient to nd any solution of the problem (
        <xref ref-type="bibr" rid="ref1">1</xref>
        ) of the lower
level.
6
      </p>
      <p>Algorithm to Solve Problem (15)
The following algorithm allows us to solve the problem (15).</p>
    </sec>
    <sec id="sec-2">
      <title>Decomposition algorithm</title>
    </sec>
    <sec id="sec-3">
      <title>Input: I; J;</title>
    </sec>
    <sec id="sec-4">
      <title>Output:</title>
      <p>= f ij gi2I; j2J ;
= f igi2I ; = f j gj2J ; F ( ; );
Step 1. (Construct matrix ^ ). For each line i 2 I of the matrix
1.1, 1.2 and 1.3, then go to step 2.</p>
      <p>Step 1.1. Build sorted line i 2 I
[i] = n (k)</p>
      <p>ij(k) :
^ [ ] [j] = n^(k)</p>
      <p>
        i(k)j :
k = 1; 2; : : : ; jJ j ; j(k) 2 J; i(j1()1)
(
        <xref ref-type="bibr" rid="ref2">2</xref>
        )
ij(
        <xref ref-type="bibr" rid="ref2">2</xref>
        )
: : :
      </p>
    </sec>
    <sec id="sec-5">
      <title>Step 1.2. Let k</title>
      <p>= j jJj+1 k ; k+ = l jJj+1 m ; i =
2 2
r (k+)</p>
      <p>ij(k+)
= j jIj+1 k ; k+ = l jIj+1 m ;
2 2
j =
r^(k+)
i(k+)j
^i((kk ))j .
execute steps
i(jjJ(jjj)j) ;
(k ) .
ij(k )
o :</p>
      <p>^(k)
(k)
Step 2.3. For k = 1; 2; : : : ; jIj let eli(k)j = i(k)j :
j
Step 3. (Normalization). Follow steps 3.1, 3.2, and 3.3, and then go to step 4.</p>
      <p>Step 3.1. Let c = r maxi2I i :
Step 4. Let F ( ; ) = Pi2I; j2J
Step 5. Return n</p>
      <p>maxj2J j
Step 3.2. For all i 2 I let i = i=c.</p>
      <p>Step 3.3. For all j 2 J let j = j c.</p>
      <p>log i j .</p>
      <p>ij
= f igi2I ;
End.</p>
      <p>= f j gj2J ; F ( ; )o.</p>
      <p>Theorem 1. Decomposition algorithm correctly solves problem (15). Its
algebraic computational complexity does not exceed the value O (jIj jJ j log (jIj jJ j)).
Proof. Monotony of the logarithmic function implies
log
i j = 0
ij</p>
      <p>, ( log ij + log i + log j = 0)
,
lij + xi</p>
      <p>yj = 0; lij = log ij ; xi = log i; yj = log j ; i 2 I; j 2 J;
Therefore problem (15) is equivalent to problem
(xo; yo) = arg min
x2RjIj i2I; j2J
y2RjJj</p>
      <p>X
j lij + xi
yj j
and there is the one-to-one correspondence between the optimal solutions of
these problems.</p>
      <p>Problem (16) is equivalent to linear programming problem</p>
      <p>X
Making the change of variables gij = fij fji; i 2 I; j 2 J in problem (19)-(22)
we get the problem of maximum weight circulation</p>
      <p>X
gij</p>
      <p>X
Let us compare problem (17)-(18) constraints system and problem (27)-(28)
constraints system. It is easy to see that the admissibility of the basic solution
(r; s; t) of problem (27)-(28) implies the admissibility of solution</p>
      <p>R = (x = r; y = s; w = fwij = tij + tji : i 2 I; j 2 J g)
of problem (17)-(18). Moreover, if (r; s; t) is an optimal solution of problem
(27)(28), then R is an optimal solution of problem (17)-(18), since dual problems
(19)-(22) and (23)-(26) have corresponding optimal solutions.</p>
      <p>The one-to-one compilation of algorithm Decomposition in terms of values
(x; y; l)) can be represented as following algorithm.</p>
    </sec>
    <sec id="sec-6">
      <title>Log Decomposition algorithm</title>
      <p>Input: I; J; L = flij i 2 I; j 2 J g;
Output: x = fxi i 2 Ig ; y = fyj j 2 J g ; FL(x; y);
Step 1. (Construct matrix L^). For each line i 2 I of the matrix L execute steps
1.1, 1.2 and 1.3, then go to step 2.</p>
      <p>Step 1.1. Build sorted line i 2 I</p>
      <p>
        L [i] = nl(k)
ij(k) :
k = 1; 2; : : : ; jJ j ; j(k) 2 J; li(j1()1)
(
        <xref ref-type="bibr" rid="ref2">2</xref>
        )
lij(
        <xref ref-type="bibr" rid="ref2">2</xref>
        )
: : :
li(jjJ(jjj)j) ;
o :
      </p>
    </sec>
    <sec id="sec-7">
      <title>Step 1.2. Let k</title>
      <p>(k+) +lij(k )</p>
      <p>(k )
= j jJj+1 k ; k+ = l jJj+1 m ; ri = lijk+)
2 2 2
.</p>
      <p>Step 1.3. For k = 1; 2; : : : ; jJ j let ^li(jk()k) = li(jk()k)
ri:
Step 2. (Construct matrix L~ ). For each column j 2 J of the matrix L^ execute
steps 2.1, 2.2 and 2.3, then go to step AUX.
Step 2.1. Build sorted column j 2 J</p>
      <p>
        L^ [ ] [j] = n^li((kk))j :
k = 1; 2; : : : ; jJ j ; j(k) 2 J; ^li((11))j
^(
        <xref ref-type="bibr" rid="ref2">2</xref>
        )
li(
        <xref ref-type="bibr" rid="ref2">2</xref>
        )j
: : :
^li((jjIIjj))j o :
      </p>
    </sec>
    <sec id="sec-8">
      <title>Step 2.2. Let k</title>
      <p>Step 2.3. For k = 1; 2; : : : ; jIj let eli(k)j = ^li((kk))j
(k)</p>
      <p>sj :
= j jIj+1 k ; k+ = l jIj+1 m ; sj = li(k+)j+^li((kk ))j .</p>
      <p>^(k+)
2 2 2
Step AUX. (Construct matrix T) For all i 2 I; j 2 J execute steps AUX.1
and AUX.2 then go to step 3.</p>
      <p>Step AUX.1 If ~lij &gt; 0, then put tij = ~lij ; tji = 0,</p>
      <p>otherwise put tji = ~lij ; tij = 0.</p>
    </sec>
    <sec id="sec-9">
      <title>Step AUX.2 Calculate</title>
      <p>End.</p>
      <p>Here an auxiliary step AUX is introduced to prove the e ectiveness of the
algorithms. The optimal values of the variables tij ; tji; i 2 I; j 2 J and the
optimal value T (r; s; t) for the problem (27)-(28) are calculated at step AUX.</p>
      <p>
        It is obvious that the solution (r; s; t), constructed by Log Decomposition
algorithm, meets all constraints of the problem (27)-(28). On the other hand
problem (23)-(26) has an integral-valued optimal solution [10], i.. in the optimal
solution g for all i 2 I; j 2 J there is an inclusion gij 2 f 1; 0; 1g. Let us
to construct the solution fgij i 2 I; j 2 J g of problem (23)-(26) using the
conditions of complimentary with respect to solutions (r,s,t) of the dual problem
(27)-(28), i.e. put
(
        <xref ref-type="bibr" rid="ref1">1</xref>
        ) gij = 1 for all i 2 I; j 2 J such that tij = 0; tji &gt; 0;
(
        <xref ref-type="bibr" rid="ref2">2</xref>
        ) gij = 1 for all i 2 I; j 2 J such that tij &gt; 0; tji = 0;
(
        <xref ref-type="bibr" rid="ref3">3</xref>
        ) gij = 0 for all i 2 I; j 2 J such that tij = tji = 0.
      </p>
      <p>It is easy to see that the constructed solution fgij i 2 I; j 2 J g is an admissible
solution of problem (23)-(26). It follows form the second duality theorem in
linear programming that (r; s; t) and fgij i 2 I; j 2 J g are optimal solutions
of the problems (23)-(26) and (27)-(28) correspondingly. The e ectiveness of
Log Decomposition algorithm, hence Decomposition algorithm, is proved.</p>
      <p>Let us to turn to the estimation of Decomposition algorithm computational
complexity. The body of Step 1 contains the sorting of the elements of the
row (computational complexity O(jJ j log jJ j)) and recalculation of its elements
(computational complexity O(jJ j)). Consequently, computational complexity of
Step 1 does not exceed values O(jIjjJ j log (jJ j) ). Analogous arguments for Step 2
lead to the validity of the assertion that computational complexity of Step 2 does
not exceed O(jIjjJ j log (jIj) ). Therefore, the total computational complexity of
Steps 1 and 2 will not exceed the values O(jIjjJ j log (jIjjJ j) ). Step 3 consists
of computation of value c and recalculation of values = f i i 2 Ig ; =
f j j 2 J g , its computational complexity does not exceed O(jIjjJ j). Step 4
consists of summing the O(jIjjJ j) elements, its computational complexity does
not exceed O(jIjjJ j) as well. Thus, computational complexity of the algorithm
does not exceed O(jIjjJ j log (jIjjJ j) ). The theorem is proved.
7</p>
      <p>Conclusion
The proposed algorithms solve the problems of analyzing the distribution of
goods by logistics centers, including a decision support system in case of
incorrectness of the task. Software implementation of these algorithms is easily
encapsulated in the MS O ce system.</p>
    </sec>
  </body>
  <back>
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