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<article xmlns:xlink="http://www.w3.org/1999/xlink">
  <front>
    <journal-meta />
    <article-meta>
      <title-group>
        <article-title>Reconstruction of images smeared uniformly and non-uniformly</article-title>
      </title-group>
      <contrib-group>
        <contrib contrib-type="author">
          <string-name>Valery Sizikov</string-name>
          <email>sizikov2000@mail.ru</email>
          <xref ref-type="aff" rid="aff0">0</xref>
        </contrib>
        <contrib contrib-type="author">
          <string-name>Aleksandra Dovgan</string-name>
          <email>aleksandra-dv@yandex.ru</email>
          <xref ref-type="aff" rid="aff0">0</xref>
        </contrib>
        <aff id="aff0">
          <label>0</label>
          <institution>ITMO University</institution>
          ,
          <addr-line>Saint-Petersburg 197101</addr-line>
          ,
          <country country="RU">Russia</country>
        </aff>
      </contrib-group>
      <abstract>
        <p>In the work, the following two variants of the direct and inverse problems about image smearing along a rectilinear trajectory are compared: 1) Uniform smearing, the same at all points of the image (smear Δ = const). This variant is described by a set of one-dimensional Fredholm integral equations (IEs) of the first kind of convolution type with direction of x axis along the smear trajectory and y is perpendicular to a smear, as well as by one two-dimensional IE of convolution type, moreover the axis x is directed horizontally and y vertically down. IEs are solved by Tikhonov regularization (TR) method (since the problem for solving them is ill-posed) and Fourier transform (FT). 2) Non-uniform image smearing of several moving objects (smear Δ = Δ (x)). This variant is described by IE of general type and solved by TR method and quadrature method (in case of set of one-dimensional IEs) or cubature method (in case of one two-dimensional IE). It is shown that in case of non-uniform smear, use of a set of one-dimensional IEs is preferable to a two-dimensional IE. The results of numerical experiments are obtained.</p>
      </abstract>
      <kwd-group>
        <kwd>Smeared image</kwd>
        <kwd>Rectilinear smear</kwd>
        <kwd>Uniform and non-uniform smeares</kwd>
        <kwd>Integral equations</kwd>
        <kwd>Tikhonov regularization method</kwd>
        <kwd>MatLab</kwd>
      </kwd-group>
    </article-meta>
  </front>
  <body>
    <sec id="sec-1">
      <title>-</title>
      <p>
        Consider one of the actual problems of distorted image processing – the
elimination of image smearing via mathematical processing ([
        <xref ref-type="bibr" rid="ref1 ref2 ref3 ref4 ref5 ref6">1–6</xref>
        ], et al.). Smearing
may be due to a shift of the image recording device – IRD (digital photo camera,
videocamera, tracking device) or the motion of the object itself (one person or
several people, cars, aircraftes) during the exposure. The problem of
mathematical elimination of smear consists of two problems: a direct problem (smear
modeling) and an inverse problem (smear elimination).
      </p>
      <p>
        To date, in a number of publications, the variant of rectilinear uniform image
smearing is considered in detail [
        <xref ref-type="bibr" rid="ref1 ref4 ref5 ref6 ref7 ref8">1, 4–8</xref>
        ], but the rectilinear non-uniform
smearing is not considered in detail [
        <xref ref-type="bibr" rid="ref1">1</xref>
        ] and the arbitrary (non-uniform
nonrectilinear) smearing is considered altogether briefly (the “blind” deconvolution
method [6, p. 192]).
      </p>
      <p>
        The purpose of this work is a comparative consideration of two variants for
straight-line image smearing – uniform and non-uniform one. Example: a
smeared image of runners on a track, running at the same, as well as at different
speeds obtained by a fixed IRD. Note that in [
        <xref ref-type="bibr" rid="ref1">1</xref>
        ], the case was considered when
an IRD during the exposure moved rectilinear with some (known) speed v(t) .
In this paper, we consider the case when the smear D(x) of the objects
themselves is known.
      </p>
      <p>
        First, we recall the well-known case of uniform rectilinear smear [
        <xref ref-type="bibr" rid="ref4 ref5 ref7 ref8 ref9">4, 5, 7–9</xref>
        ].
      </p>
      <p>The mathematical description of uniform rectilinear
image smearing
Consider the direct and inverse problems.
2.1</p>
      <p>
        The direct problem
The direct problem of uniform and rectilinear smear is described by an integral
[
        <xref ref-type="bibr" rid="ref4 ref9">4, 9</xref>
        ]:
g y (x) = D1 x+òxDw y (x) dx,
(1)
where D = const is smear value; the x and ξ axes are directed along a smear,
and the y axis is perpendicular to a smear (y plays the role of a parameter); w y
is the given non-smeared image, and g y is the calculated smeared image in
each y-line. To calculate g according to (1), we developed m-function
smearing.m [
        <xref ref-type="bibr" rid="ref9">9</xref>
        ], as well as smear.m, a simplified version of smearing.m when the smear
angle q = 0 , while in MatLab there are m-functions fspecial.m and imfilter. m
[
        <xref ref-type="bibr" rid="ref6">6</xref>
        ] for modeling g.
2.2
      </p>
      <p>The inverse problem
The inverse (more important and complex) problem can be solved in two
approaches.</p>
      <p>
        In the first approach, a set of one-dimensional Fredholm integral equations
(IEs) of the first kind of convolution type (for each value of y) is solved to
eliminate the smearing [
        <xref ref-type="bibr" rid="ref4 ref7 ref8 ref9">4, 7–9</xref>
        ]:
¥
ò h(x - x) wy (x) dx = g y (x), - ¥ &lt; x &lt; ¥ , (2)
-¥
where
      </p>
      <p>ì1 D , - D £ x £ 0,
h(x) = í</p>
      <p>î 0, otherwise.</p>
      <p>
        IE (2) is obtained from relatio (1). Here, h is mathematically the kernel of IE,
and physically and technically it is the point spread function (PSF) [
        <xref ref-type="bibr" rid="ref10 ref2 ref5 ref9">2, 5, 9, 10</xref>
        ].
The PSF is what each point of the object turns into on the image when smearing
(in a stroke). In the smearing problem, the function h is usually differential or
spatially invariant, which means that the smear is uniform and the smear value
Δ is the same at all points of the image.
      </p>
      <p>
        The problem of solving IE (2) is ill-posed [
        <xref ref-type="bibr" rid="ref11 ref12">11, 12</xref>
        ]. Therefore, we use the
stable Tikhonov regularization method (TRM) with Fourier transform (FT) [
        <xref ref-type="bibr" rid="ref11 ref5 ref9">5,
9, 11</xref>
        ]:
where
      </p>
      <p>¥
wa y (x) = 1
2p òWa y (w) e-iwx dw ,</p>
      <p>-¥
Wa y (w) =</p>
      <p>H (-w) Gy (w)</p>
      <p>
        H (w) 2 + a w2 p
is the regularized spectrum, or FT of the solution; H(w) = F(h(x)) and
Gy (w) = F (g y (x)) are the Fourier spectra of functions h(x) and g y (x) , where
F is a FT symbol; a &gt; 0 is the regularization parameter; p ³ 0 is the
regularization order (usually p = 1 or 2). To select the parameter a, a number of
methods have been developed: the discrepancy principle, the method of teaching
example-images, etc. [9, p. 236], [
        <xref ref-type="bibr" rid="ref11">11</xref>
        ]. The calculation of a restored image by the
formulas (4)–(5) is carried out according to the developed m-function
desmearingf.m [9, p. 137, 330].
      </p>
      <p>
        In the second approach, a two-dimensional Fredholm IE of the first kind of
convolution type (cf. (2)) is used to eliminate the smearing (and the defocusing)
[
        <xref ref-type="bibr" rid="ref3 ref4 ref5 ref6 ref7 ref8 ref9">3, 4–9</xref>
        ]:
(3)
(4)
(5)
¥ ¥
ò ò h(x - x, y - h) w(x, h) dx dh = g(x, y),
-¥ -¥
- ¥ &lt; x, y &lt; ¥ ,
(6)
where x and ξ axes are horizontal, and y and η are vertically down. In this case,
the PSF h will be displayed on the plane (x, y) as a narrow strip (Fig. 1) [9, p.
112]:
      </p>
      <p>
        In this approach, the calculation of the direct problem is based on the
m-functions fspecial.m and imfilter.m [
        <xref ref-type="bibr" rid="ref6">6</xref>
        ]. And the solution of two-dimensional IE (6)
(inverse problem) by the TR method and two-dimensional FT is equal to
wa (x, y) = F -1(Wa (w1,w2 )), where F -1 is the inverse Fourier transform (IFT)
wa (x, y) = 4p12 ¥ò ¥òWa (w1, w2 ) e-i(w1x+w2 y) dw1 dw2 . (7)
-¥ -¥
In (7), Wa (w1, w2 ) is regularized spectrum (two-dimensional FT) of the
solution, equal to (cf. (5))
      </p>
      <p>Wa (w1, w2 ) =</p>
      <p>
        H *(w1, w2 ) G(w1, w2 )
H (w1, w2 ) 2 + a (w12 + w2 ) p
2
where H (w1, w2 ) = F(h(x, y)), G(w1, w2 ) = F(g(x, y)) . MatLab has the
m-functi-on deconvreg.m [
        <xref ref-type="bibr" rid="ref6">6</xref>
        ] for solving the IE (6) by the TR and FT methods
according to (7)–(8). We give the well-known formulas (1)–(8) in order to compare
different approaches.
3
      </p>
      <p>The mathematical description of non-uniform rectilinear
image smearing
Based on relations (1)–(8), we consider the non-uniform rectilinear image
smearing along the smear trajectory. Suppose that from a smeared picture, we
determined in some way the dependence D = D(x) of the smear Δ on coordinate x,
directed along the smear.
3.1</p>
      <p>The direct problem
In this case, the PSF h will not be difference, or spatially invariant and the
direct problem will be written as (cf. (1)):
(9)
(10)
(11)
To solve IE (10), the FT cannot be applied, but the quadrature method is well
suited and leads IE (10) to a system of linear algebraic equations (SLAE) [9, p.
126]:</p>
      <p>Awy = g y ,
The inverse problem in case of the first approach is written as a set of
onedimensional Fredholm integral equations of the first kind of general type (for
each value of y) [9, p. 125]:</p>
      <p>b
Awy º ò h(x,x) wy (x) dx = g y (x), c &lt; x &lt; d ,</p>
      <p>a
where A is an integral operator; [a, b] and [c, d] are limits for ξ and x. PSF h
will be written as:</p>
      <p>ì1 D(x) , x £ x £ x + D(x),
h(x, x) = í</p>
      <p>î 0, оtherwise.
where A is the matrix associated with h (the same to all y-rows), w y is the
desired vector, g y is the right-hand side of the SLAE. A stable solution of the
SLAE (12) is given by the Tikhonov regularization method [9, p. 126]
where a &gt; 0 is the regularization parameter, I is the unit matrix, AT is the
transposed matrix, and w ya is the regularized solution in y-row equal to
(aI + AT A) wya = AT g y ,
wya = (aI + AT A)-1 AT g y .</p>
      <p>For computer implementation of formulas (10)–(14), the m-function
desmearq_n.m was developed.</p>
      <p>Note that the quadrature method with Tikhonov's regularization (14) can
also be used to solve a IE of convolution type (2) with PSF (3). The m-function
desmearingq.m has been developed for this.</p>
      <p>The inverse problem in case of the second approach can be written in the
form of a two-dimensional Fredholm integral equation of the first kind of general
type (cf. (6)):</p>
      <p>b d
Aw º ò ò h(x, x, y, h) w(x, h) dx dh = g(x, y),
a c
a £ x £ b, c £ y £ d .</p>
      <p>(15)
Equation (15) can be solved by a quadrature method (more precisely, cubature)
(cf. [13, p. 167]). According to this method, each of the integrals in (15) is
replaced by a finite sum on discrete node grids with respect to x, ξ, y, η and we
obtain a SLAE with a four-dimensional matrix A and a two-dimensional
righthand side g. To solve such a SLAE, one needs to transform the four-dimensional
matrix A into a two-dimensional one, two-dimensional right-hand side g to
transform into a one-dimensional one, and the resulting one-dimensional
solution w to transform into a two-dimensional one. Although the (successful)
attempt to solve a two-dimensional IE by the cubature method took place [13, p.
167–169], nevertheless, this is a cumbersome method and its use for restoration
of non-uniform smeared image is problematic.</p>
      <p>
        It is also possible to apply for solving IE (15) an iteration method, for
example, the Friedman iterative regularization method [13, p. 272], [
        <xref ref-type="bibr" rid="ref14">14</xref>
        ], which is
simpler than the cubature method, but it requires a good choice of the initial
approximation, knowledge of the parameter of the method ν, the number of
iterations, etc.
(13)
(14)
      </p>
      <p>As a result, it should be recognized that the most effective method is (10)–
(14), based on line-by-line image processing, according to which one-dimensional
IE (10) and SLAE (12) need to be solved with a two-dimensional matrix.
4</p>
      <p>Illustrative example
The following numerical example was solved. The original image of seven
runners on the track is shown in Fig. 2.
Fig. 3b shows the result of solving the inverse problem – the line-by-line
restoration of the image by the quadrature method with Tikhonov's regularization
according to (14) using the developed m-function desmearq.m. Regularization
parameter a = 10-6 (chosen by selection). We see that despite the considerable
smearing (Fig. 3a), the image is well restored, and without the Gibbs effect due
to diffusing the image edges (in Fig. 3a).</p>
      <p>The inverse problem of non-uniform image smearing
The next step is non-uniform image smearing. We suppose that the runners
run at different speeds v, which means that they have different smears D = v × T
during the exposure time T. On the basis of Figure 2, we determine the
boundaries between the runners and the values of the smears Δ runners (see Table).
As a result, a smear D(x) or D(i) is represented as a piecewise constant
function. Each runner has its own smear value within his range.
Fig. 4a shows an image smeared piecewise non-uniformly, namely, the smearing
increases from the left runner, for which smear is 5 px, to the right runner, for
which smear is 23 px, i.e. smearing is substantially non-uniform. This smearing
is performed according to (9) using the m-function smear_n.m (with diffusing
the edges).</p>
      <p>Fig. 4b shows the result of image restoration (the inverse problem) by the
quadrature method with Tikhonov's regularization according to (10)–(14) using
the m-function desmearq_n.m. Regularization parameter a = 5 ×10-3 (chosen
by selection). Fig. 4b shows that the images of the runners is restored, but with
an uneven background.
4.4</p>
      <p>The alignment of image background
The background alignment in Fig. 4b has been done: the intensity values in Fig.
4b more than 100 are replaced by 170 (this is the background value). Fig. 4c
shows the final result of image restoration after background alignment. We see
that the images of the runners are restored quite satisfactorily (cf. Fig. 3b).</p>
      <p>
        Conclusion and future plans
The described technique can be used in practice for restoring group images of
several objects (people, airplanes, cars) moving at different speeds and therefore
received different smears Δ on the image during the exposure by a fixed IRD.
In subsequent publications, the question about a method for determining
nonuniform smear Δ (x), as well as general case of smear Δ = Δ (x, y) will be
considered. Example: a smeared image of a stream of cars on a wide highway
moving at different speeds. A comparison will also be made with the technique
described in [
        <xref ref-type="bibr" rid="ref1">1</xref>
        ], which considers the non-uniform shift of a IRD. Finally, a
variant of the regularization method with the variable regularization parameter
a = a(x) will be considered. This variant should take into account the different
degrees of image distortion in Fig. 4a.
      </p>
      <p>This work was supported by the grant MFKTU ITMO (Project No. 619296).</p>
    </sec>
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