=Paper= {{Paper |id=Vol-2649/paper8 |storemode=property |title=Modelling of the Derivatives Pricing with Multifactor Volatility |pdfUrl=https://ceur-ws.org/Vol-2649/paper8.pdf |volume=Vol-2649 |authors=Ivan Burtnyak,Anna Malytska,Vitalii Gvozdytskyi }} ==Modelling of the Derivatives Pricing with Multifactor Volatility== https://ceur-ws.org/Vol-2649/paper8.pdf
92


      Modelling of the derivatives pricing with multifactor
                            volatility

                   Burtnyak Ivan1, Malytska Anna2, Gvozdytskyi Vitalii 3

                  1, 2
                    Vasyl Stefanyk Precarpathian National University, Ukraine,
                                      bvanya@meta.ua
              3
                Simon Kuznets Kharkiv National University of Economics, Ukraine,
                                  gvozdikramm@gmail.com



       Abstract. The pricing of options generated by diffusion processes, where diffusion
       depends on two groups of variables, was carried out. An algorithm for calculating
       the approximate price of derivatives and the accuracy of valuations has been
       developed, which allows to perform the analysis and to make precautionary to
       minimize the risk of derivatives pricing arising on the stock market. The method of
       finding the indicative price for a wide class of derivatives has been expanded. Using
       the spectral theory of self-adjoint operators in Hilbert space and the wave theory of
       singular and regular perturbations, an analytical formula of the approximate asset
       price was set, which was described by models with stochastic volatility dependent
       on l-fast variable and n-slow variable factors,                               and on
       local variable.

       Keywords: derivative pricing, diffusion processes, Ornstein-Uhlenbeck process,
       spectral theory, singular and regular perturbation theory, stochastic volatility, Sturm-
       Liouville theory, Vasicek model.


I Introduction

   At the moment, financiers have been drawn to the problem of the relationship between
the price of an asset and its volatility. The asset price was found to be volatile. This has
led to a number of works to refine this model. Empirical studies have shown that volatility
is a time-dependent random variable [5]. Analytical models having stochastic volatility
are proposed in [6]. In particular, they provide an opportunity to examine the price of
assets that change continuously over time [7-10].
   A spectral image of the density of one-dimensional diffusion was obtained in [12].
Spectral theory is an important tool for the analysis of financial models of diffusion in the
study of the decomposition of the eigenfunctions of linear operators. Spectral theory has


Copyright © 2020 for this paper by its authors. Use permitted under Creative Commons
License Attribution 4.0 International (CC BY 4.0).
                                                                                           93

been used by many scientists, namely to forecast options prices [9], to find interest rate on
securities [14], to simulate volatility of financial assets [13]. Both spectral theory and
stochastic volatility models have become an indispensable tool in financial mathematics,
due to the fact that derivative prices are subject to Brownian motion and correlate with
volatility [1]. Study of stochastic volatility, in particular the volatility of an asset
controlled by non-local diffusion [2].
    Short-term interest rate dynamics models were considered in Vasicek's work [11] for
derivatives pricing. Significant contribution to the theory of interest rates was made in [8-
10], namely: finding the credit spread of credit market instruments, determining the price
of interest rate options, determining the risk and return on derivatives of the stock market.
The models developed by these scientists have their advantages and disadvantages, but
each is used to increase the liquidity of the financial markets. The use of more complex
models, despite their theoretical validity, causes complex multi-parameter functions of the
profitability curve to be obtained, and this causes significant errors in the calculations.
    Using spectral analysis, Linetsky [5] applied the spectral theory of self-adjoint
operators to different models, and in particular to the Vasicek model. Lorig [11]
considered short-term interest rates described by Vasicek's model with stochastic
volatility dependent on two factors, one of which is fast and the other is slowly changing.
The spectral theory and the theory of singular and regular perturbations is applied to self-
adjoint operators in Hilbert spaces, which describe processes with multidimensional
stochastic volatility having l-fast variable, n-slow variable factors,
  . In particular, this theory applies to the short-term interest rates described by Vasicek's
model. The approximate price of the bonds and their profitabilty are calculated. Applying
the Sturm-Liouville theory, Fredholm alternatives, and analyzing singular and regular
perturbations at different time scales, we obtained explicit formulas for the approximation
of bond prices and profitability.
    The goal of the article is to develop an algorithm for finding the approximate price of
derivatives and to find explicit formulas for finding their value based on the development
of eigen functions and eigenvalues of self-adjoint operators using boundary tasks for
singular and regular perturbations. To set the theorem of estimating the accuracy of option
prices approximation.
    The main advantage over other developed methods is that finding the price of
derivatives is reduced to solving the problem of finding the eigenvalues and
eigenfunctions of a particular equation that fits this model.


II Methodology and Data

   Let represent short interest rates. One of the most widely known models of short
interest rates is the Vasicek model, in which       is modeled as an Ornstein-Uhlenbeck
process with multidimensional stochastic volatility.
94

  The Ornstein – Uhlenbeck process is described by a second-order differential equation
ща parabolic type
                                        (           )                    (        )           (        )       (   )   ( )

  Let’s calculate the density of distribution of this process. To do this, consider the
Cauchy problem for (1). With the initial condition
                                     (    )      ( )                               ( )
where       ( ) – smooth finite function.

     Let’s apply the Fourier transform. In particular,

                                (       )                           ∫             (       )
                                                    √

     i.e.

                                (       )                           ∫             (       )
                                                    √

     Then equation (1) reduces to equation
                                                (               )                             (            )           ( )

     We will take into account that

                               ∫                        (           )                 [            |
                         √                                                √


                (∫                  (       )                   ∫             (       )       )]


     The initial condition has the form
                                                (           )           ( )                                            ( )
    The Cauchy problem (3), (4) for a linear non-uniform differential equation in partial
first-order derivatives is solved by the method of characteristics

                                                        (                     (               ))


                                                                                                                       ( )
                                                                                                                                       95


                                                                                                                                       ( )
                                                          (                        (             ))

(5) and (6) are equations of characteristics.
   From (5) we have the equation
     | |
  Substitute in (6)


                                          (                            (                         ))


             ∫             ∫(                             (                            ))



                                          {∫ (                                 (                      ))          }


  With           ,   (̂)            ̂    ̂.
  Then       on the characteristics has the form
                                       (         )                                                        (               )
              (      { })       {                                                            (                                    )}

                                                      (                    )                                  (               )
   (     )         (           { })           {                                                  (                                 )}


                   (       )          ∫(          {           }) (         )                         ∫(       {       })
                                √                                                       √

                           (               )                                   (                 )
               {                                               (                                          )} (        )

                                                                                   (                  )
                                ∫          {                  {
                       √

                                                  (                )                   ( )
                                      (                                )}}
96


                                                                                                                         (                    )
                   ∫       ( ) ∫             {                         {(                            )
               √

                               (                 )                                                                           (                )
                       (                                 )}}                                                 ∫
                                                                                    √

                           (                 )                                               (                           )
                   {                                                   (                                                             )}

     Let’s distinguish the complete square by
                 (          )                                                   (                            )           (                    )
                                      (                                                                          )
                                                                                                                                 √
                       √                                                (                            )
                                         (                                                            )
               (           )                                                                                             (                    )

               (           )                                            (                                )                       √
           (                             (                                                                   )                                    )
                       √                                                                                             (                    )

                                                         (                  )
                           (                                                    )
                                                                                             (                               )
     Having replaced
           (         )                                             (                             )                           √
                                     (                                                               )
                   √                                                                                         (                       )            √
     using the Cauchy integral theorem
                                                                                                         √
                                                     (             (                ))
                                                                                             (                       )

               ∫                                                        ∫                                                                             ( )
       √                       √
                                                                                                     √
                                                 (             (                ))
                                                                                         (                       )



     Indeed ∮( )                   – closed contour,                                – analytical function, so, by Cauchy's
integral theorem, the integral is zero.
                                                                                                      97




  Fig. 1. Contour of integration

  Let’s take contour (                ( )) as ( ), where
                                         (           (                    ))√
                                                (        )
with (           (           ))               if                  , the contour is arranged symmetrically

along the axis        with                    ∫           will transform into ∫       , and ∫     ∫   .


                                          ∫                           ∫                               ( )


with         therefore equality (7) holds.
   Let's check that goes to zero at
                                      |           |
                                                      (       )
                                                                                  |   |
                 |∫          |        |∫                              |                   |   |

                                  |       |
   With fixed                                                 then because

                                                            ∫
98


     Similarly, ∫                                            . Will get
                                                                          (                )
       (   )                ∫       ( )        { (                                             )                           }
                   √                                                                                   (                  )

     so fundamental solution or the Green's function has the form

                                                                      (                        (                 ))
               (        )                                         {                                                   }
                                √         (              )                            (                    )


                                                              (           (           )(                   ))
                                                        {                                                       }
                    √           (             )                               (                    )

    On the other hand, on the probabilistic side, the Green's function is the density of
distribution.
    Using the methods of spectral theory and the theory of singular and regular
perturbations, we can find the approximate price of Ornstein-Uhlenbeck two-barrier
options with multivariate volatility, as a self-function decomposition using infinitesimal
generators of (l + n + 1)-dimensioned diffusions,                                  that is,
diffusion depends on one local variable, the l-dimensional fast-variable factor and the n-
dimensional slow-variable factor. This work is an extension of [6, 11, 13], in [11] l = 1
and n = 1.
    Process     can represent many economic phenomena and processes. For example,
inventory value, index price, reliable short interest, etc. More broadly, is an external
factor that characterizes the cost of any of the above processes. By physical measure of
process , we understand process , which has an instant drift ( ) and stochastic
volatility ( ) (                          )     , which contains both components: local
  ( )and non-local (                            ). It should be noted, that infinitesimal
generators for and have a form
                   (         ( )                  ( )         )                   (       ( )                    ( )       )

are characterized by the values                   and       respectively. Thus,                            and                 have
an internal timeline                 and                Let’s consider                         and                    , to make the
inner time scale            small and the inner time scale                    – large. Therefore,                               are
fast variables, and                           are slowly variable factors. Note that                                and        have
the form of the Ornstein-Uhlenbeck process [20]
                                                                                                                               99


                                               ̅
    the right part of which has a form
                   ̅                                                                          (9)
    Let’s reduce (9) to the equation                  , where              , so that there is no
first derivative in the obtained equation, that is, we look for a solution in the form
                                              ( ) ( )
where    (  )   new unknown function, and let’s choose ( ) in such way to have
                                 ( )      .                                                 (10)
          Having reduced into (10), we will have ̅                      , herefrom
                        ( )                { ∫                     }           {                       }
                                                       ̅                               ̅
                  ( )          (           )       (           )
                                   ̅                   ̅                   ̅               ̅               ̅
   will have
                                                           (               )
                                               ̅                   ̅
   Thus,
                                       ( ) ( ), де ( )                         {                       }
                                                                                       ̅
   In our case
                          ( )          {       }    ( )    ( )
                               ̅         ̅
   In order that in equation (10) was not a function of ( ) but                                                        , then we
replace the variables     ( ) in (9).


substituting in (10) we obtain
                           ̅                       (                   ̅           )                                       (    )
   Let’s apply to (11) the same considerations as in (8)                                           then
                                                                   ̅
                                   { ∫                                             }               √
                                                           ̅
   Let’s write the value of new            ( ).
                                               ̅                                           ̅
            ( )          (                                     )       (                                   )
                                       ̅                                       ̅                                   ̅
                                                                                               ̅
   For reasons of solution, let's make a substitution                                      {           } to find
                                                                                               √
100

                                 ̅                                        ̅                                               ̅
                      (                  )       (                                )                     (                     )
                       √ ̅      √                    √ ̅              √                                     √ ̅           √
                                                      ̅
                                         (              )
                                             ̅
we will have
                                                                  ̅
                                             ( (                      )               )
                                                      ̅
                                 ̅                                                                           ̅
                           (         )                                                        √ (                )
                           ̅                                                                        ̅
    need solution to be equal 0 at points                         and            , and     and                           do not give such a
picture, so we will replace the variables                                     , we’ll have
                              ̅                                       ̅
                                      ( (                                 )               )
                                                          ̅
or
                                         ̅
                                                          (                   )
on eigen values and eigen functions we will explore
      ̅                              ̅
              (       )
then
                 ̅                                                                                                   √
                                                                                      ̅                              ̅
           The general solution has the form
                                        √                                                     √
                                      (      )                                            (                 )
                                         ̅                                                     ̅
      Let’s check the fulfilling of boundary conditions, if                                             then                  , with      ,
                                    √                                     √
                                (                     )
                                     ̅                                        ̅
therefrom
                                             ̅                                                     ̅
                                                                  ( )
                                    √                                                         √
     From the point that

                                                              ̅
                                 ∫
                                                 √
     We have
                                                                                                                                                           101


                                                                           ̅                               ̅
                                                                  √                                    √

                                                              √                                √

                              ̅                                        ̅                                                                       ̅
          ( )         (           ) (                     (                )           )√                      {               }
                                                              ̅                                                        ̅
                                                                                                                                           √
   Let’s find the scalar product
                                                      ̅
          (       ( )         ( ))        ∫                           {                    }           (               )       (                   )
                                                                               ̅
                                                                                                           √                       √

                              {           }                            ∫               (                   )       (               )
                  ̅               ̅


                  ∫                                                   ∫[           (               )               (           )       ]

                                      (           )                            (               )
                                                          |                                            |
                                  (           )
   With

                      ∫                           ∫(                                   )                                   |

   Thus,
                                          (           ( )                 ( ))         {
III Results and analysis
    Let     be the securities without paying dividends on an asset (for example, stock,
index, etc.). Often, is modelled as a geometric Brownian motion with constant volatility
(e.g. Black-Scholes formula) [7]. Consider as a model of geometric Brownian motion
with multidimensional stochastic volatility. In particular, ̃ dynamics in are given by:
                                    (                    ) ̃ , ( )
    Let’s calculate the approximate price of the double barrier of the option defined on .
    Let us write down the operator 〈 〉 and its associated densities at speed ( )
      〈       〉           ̅                                                    ( )               (      )                                      (       )
                                                                                      ̅            ̅
   For a double barrier option with                               and          barrier values, the payout is:
102

                   ( ) { } (               ) { },        (      ),                ,
    To calculate the value of this parameter, at first, it is needed to find the eigenvalues of
the operator 〈 〉 with boundary conditions
                                        ( )      ,             ( )    .
    It should be noted that a regular killing of boundary conditions at the ends and are
entered. Equation
        〈 〉                               (〈 〉)
    with the above boundary conditions can be found in [4]
                               ̅√                                                                 ( )
                 ( )                            (                        )        (                     )
                                                         ̅                                    ( )
                           √       ( )

                                                ̅                                                                       ̅
                                 )     ((     )
                             ( )                                                                                ̅
   Let’s write down expressions for operators and
                                                                                                                                      .       (   )
   On the basis [12] let’s calculate                             ,               and ̃            . For                 let’s find
                                                                     (            (       )        )
                                                                 (                                          )
                                                                     (                )̅           ( )

                 (         (        )       )        (                   ̅        (                         ̅           ̅ )       ( ))

                                                         (                    )̅              ( )
             (                                                                                                                            )
                                                                 (                (       )        )
                                                             (               )(               )    ( )
                                                                             (            (        )        )               ( )
                 ̃                  ̅(           )               ̅ (                                                              )
                                                                                      (                 )           ̅
                                                             ( ( )                (   )                ( ))
                                                             (                   )̅           ( )

             (         (       )        )       ((               )(               )   ̅                 (               ̅ )       ( ))

                                                    (                    )        ̅       ( )
   And for             let’s find
                                                                                                                                                103



                                           (           (                              )             (                         )
                                               ̅                ( )                            ̅                        ( )


                                                   (        (                              )            ))
                                                       ̅                             ( )            ̅

                                                                                      ̅
                                                                     (                    )
                                                                                 ̅
                                   (               ( )               ( ))                                         (     ( )             ( ))
    ̃            ̅ (                                                             )             ̅ (                                          )
                          ̅    ̅     ( )                                                                ̅               ̅         ( )
   Calculation    can be found in [1-2]
                                                                         ̅
                      (       () (                  ) )                              (         (            ̅)           ( ))
                                                                         ( )

                                                               ( )
             (    (       )(                   (           )                 (            )             (        )(     )         )
                                                                             ( )                                 ( ).
                                                                     ̅                                  ̅
    The approximate price of the options can always be calculated and plotted,
individually in each respective timeline, in the same way as for two components [3].
    Let’s calculate the approximate price of a zero coupon bond.
    Let’s write the operator 〈 〉 and its associated densities at speed ( )
                               〈     〉                 ̅                 ( ̅              )                                                 (     )

                      ( )          (    ( ̅    ) )                                                  ̅                 ̅̅̅̅
                            ̅        ̅
   For a zero coupon bond, the full payout is:
                                       ( )      {   }                                                                                       (     )
   The differential equation corresponds to operator 〈                                             〉.
                                           ̅                    (                )
  Let's make a substitution to avoid the first derivative in the obtained equation:
                                                   ( )
                            ( ) ( )      ( )           ( )     ( ) ( )
                     ( )       ( ) ( )          ( ) ( )       ( ) ( )
where ( ) unknown function, ( ) will be picked from the obtained equation
         ̅ ( )     ( )             ̅               ( ) ( )                       ̅         ( ) ( )
                                       (                   )( ( ) ( )                         ( ) ( ))                  ( ) ( )
104

therefrom
                                               (           ) ( )            ̅        ( )
i.e.
                         ( )                   (           )                                          (                   )
                                                                           ( )                  {                             }
                        ( )                        ̅                                                         ̅
       We will get the equation
                     ̅ ( )         ( )       ( ̅           ( )         (             ) ( )                       ( )) ( )

       Because
                                                                           (           )
                                                   ( )                 {                    }
                                                                                 ̅
then
                                                           (           )              (                 )
                                         ( )                                     {                           }
                                                               ̅                           ̅̅̅̅
                                                               (            )                           (                 )
                               ( )       (                                       )         {                                  }
                                                                   ̅                                             ̅
       By substituting we will get
                (          )       √                                                                (                             )      (       )
                               ̅
                                                                   ̅                                ̅
                                                   (√                      )

                    √                             ̅
                        (     ̅)             ̅
                     ̅
  Let’s substitute all values of variables into
                                 ̅                  ̅ √                                                                       ̅
                        (√          )          (         (                                                   ̅)                   )
                                                       ̅
                                      √               ̅
                                     ( (         ̅)      )
                                       ̅
where ̅          ̅̅̅̅ and - the Hermite polynomial.
       Let’s find the scalar product(                  ( )         ( )):
                                                                       ̅                                          ̅                      ̅
            (        ( )       ( ))          ∫ √                                                    (                 (             ̅)       )
                                                        √
                    √                    ̅                 √                          ̅
             (         (       ̅)            )         (      (             ̅)              )                         (       (          ̅) )
                     ̅                                      ̅                                     ̅                       ̅
                                                                                                                      ̅
                               √                           ∫               { (        (                 ̅)                    ) }
                                    √                                            ̅
                                                                                                                                           105


                             √                              ̅                  √                                       ̅
                         (      (              ̅)               )          (      (                   ̅)                   )
                              ̅                                                 ̅
                                           √                               ̅
   After replacing the variable                     (           ̅)                           we will have
                                               ̅


           (   ( )           ( ))                                          ∫             {            }            ( )         ( )
                                           √

                                                   ∫(           )
                             √
   Because
                             ( )                   ( )                                                             (       )
            ∫ (          )         (           )                     (         )     ∫ (                       )


                                       (       )         ∫ (               )

therefrom it follows that
                                               ( )                       ( )
                         ∫ (               )            (            )                   {

                                                                                                                                   (   )
                         ∫ (                            )                                    ∫                         (       )
               √                               √
   By integrating by the parts, given that such an integral contains pair degrees
decreases and reduces to ∫              and integral which contains        – not pair equals
zero,    times, taking by parts we will get ( ( )      ( ))
   To find the price of the bond with payments ( )          {   }    , it’s needed to solve
the equation (15) on finding the eigenvalues at the segment          (          ) with 〈 〉,
according to (15). As both ends      and are natural boundaries, then the solution has a
form [3]
                   ̅                 ̅ √                 ̅        √                ̅
           (√          )        (            (     ̅)      )     ( (         ̅)       )
                                          ̅                        ̅
       – the Hermite polynomials [18], which have a form
                                                                               [ ]
                                                                                     (        )
                     (        )                         (            )         ∑
                                                                                                           (               )
   Let’s write down expressions for operators                                        and          :
                             (          )
106

   Operators                                 ̃               are written on the basis of recurrence ratios:


                                                                                           √
                                        {∑ ( )(                           )        (         )                                                       }
                                                                                           ̅   (                                 )

                                                                                           √
               (                       ){∑ ( )(                          )         (         )                                                       }
                                                                                           ̅   (                                )
                                                                            √
                                            {(           )               (     )                                                             }
                                                                             ̅ (                            )
                                                                           √
                                       {(            )                   (    )                                                          }
                                                                           ̅ (                         )
                                                                                                           ̅
                                   ̃                                 ̅ {[(        )(                                        )]
                                                                                               ̅                        ̅
                                                             √                         ̅
                     [(           )(         )           (     )(                                          )]
                                                             ̅    ̅                                    ̅        (                )
                                                                         √
                                  [(        )(           )           (     )(              )]
                                                     ̅                   ̅                         (                )
                                             √
                                       [(      ) ( )]                                                                   }                ̅
                                             ̅    ̅ (                              )
               ̅
      {(                      )              (           )                                                          (           )                        }
           ̅              ̅                                  (               )                                              ̅        (           )

           ̅̅̅̅ {(        )                 (            )                                                          (           )                        }
                                                                 (           )                                          ̅            (           )
                                                 ̅
                                       ̅̅̅̅ {(               )                (            )                                                     }
                                                                                  ̅√           (                )
   Calculation of                 can be found in [1-3]
                                               √             (           )
                                             ̅
    For zero coupon bonds, the profitability curve is considered more often rather than the
price of the bond itself. Return     in zero-coupon bonds, for which one dollar is paid at
time is determined by the ratio:
                                                                                       (                    )
   Let’s get an approximation for a zero coupon bond, sorting it out both bond prices
     and return      by degrees √ and √ :
                                                                                       107



                                ∑√              ∑√


                        { (           ∑√             ∑√           ) }


                          ∑√                         ∑√

   Grouped by degrees√        and √   we will get:

                                       ∑√              ∑√


                          (       )

    Note: the drawings are built by component in each corresponding timeline, similarly
for the two components as in [2].


IV Conclusions

   Thus, the studies conducted in the work allow us to draw the following conclusions.
   An algorithm for finding the approximate price of derivatives has been developed and
explicit formulas have been found for finding their value based on the decomposition of
eigen functions and eigenvalues of self-adjoint operators using boundary tasks for singular
and regular perturbations. The theorem of estimating the accuracy of derivatives prices
approximation is established, on the scales of systems of slow and fast variable factors on
which volatility of derivative financial instruments depends.
   The general method of finding the approximate price for a wide range of derivatives
has been obtained. It has been established that derivative payments can be path-
dependent, and the underlying process may exhibit a jump whose intensity depends on
multidimensional volatility. The price of options depends on the stochastic
multidimensional volatility, which is described by a path-dependent process. Finding the
price of derivatives comes down to the task of finding the eigenvalues and eigenfunctions
of a particular equation that fits this model.
   The approximate price of bonds and their profitability are determined by the methods
of spectral theory and wave perturbation theory. The spectral theory and the theory of
singular and regular perturbations have been applied to short-term interest rates described
by the Vasicek model. The approximate price of the bonds and their profitability are
calculated.
108

    The main advantage of the reviewed pricing methodology is that, by combining
methods with spectral theory, regular perturbation theory and singular perturbation theory,
it reduces to solving equations on finding eigenfunctions and eigenvalues.


References
  1.       Burtnyak І.V., Malytska A.: The Investigation of Securities Cost Using Methods of
   Spectral Analysis. International Journal of Economic Research, Vol. 14, Issue 15, pp. 705–715.
   (2017)
  2.       Burtnyak І.V., Malytska A.: The Evaluation of Derivatives of Double Barrier Options of
   the Bessel Processes by Methods of Spectral Analysis. Investment Management and Financial
   Innovations, Vol. 14, Issue 3, pp. 126–134. (2017)
  3.       Burtnyak І.V., Malytska A.: Spectral study of options based on CEV model with
   multidimensional volatility. Investment Management and Financial Innovations, Vol. 15(1),
   pp. 18-25. (2018)
  4. ---- Cartea, A., Jaimungal S.: Risk metrics and fine tuning of high-frequency trading strategies.
   Mathematical Finance, 25 (3), pp. 576–611. (2015)
  5.       Linetsky V.: Sticky reflecting Ornstein-Uhlenbeck diffusions and the Vasicek interest rate
   model with the sticky zero lower bound. Operations Research, Vol. 51(2), pp. 185–209. (2019)
  6.       Lorig, M., Pagliarani S., Pascucci A.: Analytical expansions for parabolic equations.
   SIAM Journal on Applied Mathematics 75, 468–491. (2015)
  7.       Lorig, M., Sircar R.: Portfolio optimization under local-stochastic volatility: Coefficient
   taylor series approximations and implied sharpe ratio. SIAM Journal on Financial Mathematics,
   7 (1), pp. 418–447. (2016)
  8.       Mendoza R., Linetsky V.: Pricing equity default swaps under the jump-to-default
   extended CEV model. Finance and Stochastics, 15 (3), pp. 513–540. (2010)
  9.       Mendoza-Arriaga R., Carr P., Linetsky V.: Time-changed Markov processes in unified
   credit-equity modeling. Mathematical Finance, Volume 20, pp. 527–569. (2010)
  10. Obizhaeva A., Wang J.: Optimal trading strategy and supply/demand dynamics. Journal of
   Financial Markets, 16 (1), pp. 1–32. (2010)
  11. Pagliarani S., Pascucci A.: Analytical approximation of the transition density in a local
   volatility model. Cent. Eur. J. Math., 10 (1), pp.250–270. (2012)
  12. Schied A.: Robust strategies for optimal order execution in the almgren–chriss
   framework. Applied Mathematical Finance, 20 (3), pp. 264–286. (2013)
  13. Wendong, Z., Kuen K. Y.: Closed form pricing formulas for discretely sampled
   generalized variance swaps. Mathematical Finance, 24 (4), pp. 855–881. (2014)
  14. Wu L,. Carr P.: A Simple Robust Link Between American Puts and Credit Protection. The
   Review of Financial Studies, 24(2), pp. 473–505. (2011)