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<article xmlns:xlink="http://www.w3.org/1999/xlink">
  <front>
    <journal-meta />
    <article-meta>
      <title-group>
        <article-title>On the Modeling Process of Ultrasonic Wave Propagation in a Relaxation Medium by the Three-Point in Time Problem</article-title>
      </title-group>
      <contrib-group>
        <aff id="aff0">
          <label>0</label>
          <institution>Danylo Halytsky Lviv National Medical University</institution>
          ,
          <addr-line>Pekarska str., 69, Lviv, 79017</addr-line>
          ,
          <country country="UA">Ukraine</country>
        </aff>
        <aff id="aff1">
          <label>1</label>
          <institution>Lviv Polytechnic National University</institution>
          ,
          <addr-line>Bandery str., 12, Lviv, 79013</addr-line>
          ,
          <country country="UA">Ukraine</country>
        </aff>
      </contrib-group>
      <abstract>
        <p>A mathematical model of the process of ultrasonic oscillations in a relaxation medium with known acoustic wave profiles at three points in time is proposed. The model is reduced to the study of a three-point problem for a hyperbolic equation of third order, which is widely used in ultrasound diagnostics. A differential-symbol method for constructing a solution of the three-point problem is proposed and a class of quasipolynomials as the class of uniqueness solvability of the problem is found. The technique which specified in the work allows to investigate in detail the main parameters of acoustic oscillations in problems of ultrasonic diagnostics. The method is demonstrated on specific examples of three-point problems.</p>
      </abstract>
      <kwd-group>
        <kwd>1 Mathematical model</kwd>
        <kwd>acoustic oscillations</kwd>
        <kwd>three-point problem</kwd>
        <kwd>differential-symbol method</kwd>
        <kwd>ultrasound diagnostics</kwd>
      </kwd-group>
    </article-meta>
  </front>
  <body>
    <sec id="sec-1">
      <title>-</title>
      <p>1. Introduction
 
is investigated. In
2 2 2
x12
x22</p>
      <p>x32</p>
      <p>In the theory of mathematical modeling there are many models of processes of various nature.
Increasingly, these models from some areas of knowledge are used in other areas. In particular,
modeling of hydromechanics and gas dynamics problems [1, 2] is successfully used in modeling
biomechanical and medical processes [3-5].</p>
      <p>
        Modern mathematical models increasingly contain partial differential equations, both linear and
nonlinear. Therefore, the research of such models is quite complex and their study involves powerful
numerical, qualitative and asymptotic methods (in particular, see [6, 7]). In addition to traditional
partial differential equations of the second order, which are actively studied in the equations of
mathematical physics, there are often partial differential equations of the third order in time in
mechanical, biomedical and geophysical models [8-11]. Among the problems of ultrasonic
diagnostics in [12-14] the Cauchy problem for the hyperbolic equation of the third order of the form
3, (
        <xref ref-type="bibr" rid="ref1">1</xref>
        )
equation
(
        <xref ref-type="bibr" rid="ref1">1</xref>
        ), 
is relaxation time,
u(t, x )
is
dynamic
pressure,
is three-dimensional Laplace operator, t   / t , constants c1 and c2 are
limiting phase speeds of sound.
      </p>
      <p>In addition to the Cauchy problem for partial differential equations, multipoint in time problems
with the given values of the unknown solution not at only one time point, but at several moments of
time are intensively studied. In particular, papers [15–18] and [19, 20] are devoted to problems with
multipoint in time conditions in bounded and unbounded domains respectively. Problems with n
point time conditions have a simple physical interpretation, namely in these problems the state of the
research process at n different time points are given. However, despite of the simplicity of physical
interpretation, multipoint problems are not easy to study. In contrast to the Cauchy problem, the
kernel of multipoint in time problems is nontrivial [21, 22]. Therefore, the study of the corresponding
incorrect multipoint problems for partial differential equations requires new research methods, among
of them, the differential-symbol method is especially effective [23–26].</p>
      <p>The aim of this work is:
 study of a mathematical model describing the motion of an ultrasonic wave in a relaxation
medium with given profiles of the wave at three time points;
 establish the class of existence and uniqueness of the solution of the corresponding
threepoint in time problem;
 recommend the method for constructing the solution of the problem;
 development of a method for determining the influence of the wave process parameters under
the condition of specific initial data of the three-point problem.
2. Posing of the problem and main results</p>
      <p>By replacing x 
hyperbolic equation
x
c1</p>
      <p>
        c
,   1 , ultrasonic wave equation (
        <xref ref-type="bibr" rid="ref1">1</xref>
        ) is transformed in the one-parameter
      </p>
      <p>c2
t3  t  t2   u(t, x)  0, (t, x)  (0, ) 
3.</p>
      <p>
        (
        <xref ref-type="bibr" rid="ref2">2</xref>
        )
      </p>
      <p>
        Let’s note that the spatial varixabalend the parameter  in equation (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ) are dimensionless,
moreover  belongs to the interval (
        <xref ref-type="bibr" rid="ref1">0,1</xref>
        ) .
      </p>
      <p>
        We consider the mathematical model of the process of an ultrasonic wave propagation which is
described by equation (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ), if the profiles of wave are given at three equidistant moments of time
t  jh, j  J  {0,1, 2}, h  0 :
u( jh, x)  f j (x), j  J , x 
3.
      </p>
      <p>
        To study the three-point problem (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ), (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ), we use the differential-symbol method which was
previously [23] used to solve the two-point in time problem. Based on the differential equation (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ), for
the unknown function   (t, ) we write the corresponding ordinary differential equation with the
parameter 
where i2  1, A  3 B 
4(3  1)3  B2 , B  27  9  2 .
(
        <xref ref-type="bibr" rid="ref3">3</xref>
        )
(
        <xref ref-type="bibr" rid="ref4">4</xref>
        )
(
        <xref ref-type="bibr" rid="ref5">5</xref>
        )
(
        <xref ref-type="bibr" rid="ref6">6</xref>
        )
in which  |  |2  12  22   2 ,   (1,2 ,3 ) 
3
      </p>
      <p>3 , dt  d / dt .</p>
      <p>
        Taking into account the dependence    2 , let us denote the roots of the characteristic equation
for (
        <xref ref-type="bibr" rid="ref4">4</xref>
        )
by 1  1( ) , 2  2 ( ) , 3  3 ( ) . These roots have the following form
dt3  dt2   dt   (t, )  0 ,
      </p>
      <p> 3   2     0 ,
1  1( )  
2  2 ( )  
3  3 ( )  
1
3
1
3
1
3



3А 3 4
3А 3 4
3 2(1  3 )
3A
</p>
      <p>
        A
(, )   1,1 , there are at least two different roots among the roots of (
        <xref ref-type="bibr" rid="ref6">6</xref>
        ). If
 9 3
 (4 2 27 2 18 4  )  0 there are simple roots.
      </p>
      <p>
        Remark 2. For   0 equation (
        <xref ref-type="bibr" rid="ref5">5</xref>
        ) has the form
      </p>
      <p>3 2  0
and the roots 1  1, 2 3  0 do not depend on  .</p>
      <p>
        For the ordinary differential equation of third order (
        <xref ref-type="bibr" rid="ref4">4</xref>
        ) we construct a fundamental system of
solutions 0(t,), 1(t,), 2(t,), which satisfies local three-point conditions
This system can be formed only for vectors   3 which fulfill the condition
k  jh,   10,, kk  jj,, k, jJ .
      </p>
      <p>()  detgk( jh,)k,jJ  0 .</p>
      <p>We get:
gk(t,)  ek1()t for simple roots 1 2 3 1,
gk(t,) tke1()t for triple root 1() ,
g0(t,)  e1()t, g1(t,)  e2()t, g2(t,) te2()t for 1 2 3 .</p>
      <p>
        Let’s denote E1  e1()h, E2  e2()h, E3  e3()h for 1 2 3 1. For condition (
        <xref ref-type="bibr" rid="ref8">8</xref>
        ) the
elements of system 0(t,), 1(t,), 2(t,) have the following form
0(t,)  E3E2(E3  E2)e1()t  E3E1(E3  E1)e2()t  E2E1(E2  E1)e3()t
()
,
1(t,)  (E32  E22)e1()t  (E32  E12)e2()t  (E22  E12)e3()t
()
,
2(t,)  (E3  E2)e1()t  (E3  E1)e2()t  (E2  E1)e3()t
()
,
where () E3  E1E3  E2E2  E1 .
      </p>
      <p>If 1 2 3 , then ()  hE2 E2  E12 . The functions 0(t,) , 1(t,), 2(t,) take the
form
0(t,)  hE23e1()t  hE1E2(2E2  E1)e2()t  E1E2(E2  E1)te2()t
()
,
2(t,)  hE2e1()t  hE2e2()t  (E2  E1)te2()t .</p>
      <p>()</p>
      <p>
        In the case of triple root of equation (
        <xref ref-type="bibr" rid="ref5">5</xref>
        ), that is 1 2 3, we have ()  2h3E13  0 for each
  3, for which | |2 1 . The functions 0(t,), 1(t,), 2(t,) get the following form
3
(
        <xref ref-type="bibr" rid="ref7">7</xref>
        )
(
        <xref ref-type="bibr" rid="ref8">8</xref>
        )
(
        <xref ref-type="bibr" rid="ref9">9</xref>
        )
(
        <xref ref-type="bibr" rid="ref10">10</xref>
        )
0(t,)  1 3 t  1 t2 e1()t,
      </p>
      <p> 2h 2h2 
1(t,)  2  ht  ht e1()(th),
2(t,)  h  t t e1()(t2h).</p>
      <p>
        2h2
()  h1eh 2  0. The functions (
        <xref ref-type="bibr" rid="ref8">8</xref>
        ) take the form
g0(t)  0(t,)  20  het  heh(2 eh)  eh(1eh)t
h(1 eh)2
,
g1(t)  1(t,)  20  2heth(12he(h1)2e2h)t ,
g2(t)  2(t,)  20  het  h  (1 eh)t
h(1 eh)2
(
        <xref ref-type="bibr" rid="ref11">11</xref>
        )
(
        <xref ref-type="bibr" rid="ref12">12</xref>
        )
(
        <xref ref-type="bibr" rid="ref13">13</xref>
        )
and do not depend on parameter  . The graphical representations of these functions for h 1 are
given in Figure 1. Dashed lines on Figure 1 indicate asymptotes.
in which Q(x) is nonzero polynomial of variables x1, x2 , x3 with complex coefficients,  1, 2 , 3 are
complex parameters, the vector   ( 1, 2 , 3) satisfies condition (
        <xref ref-type="bibr" rid="ref8">8</xref>
        ), that is   M , where the set M
is determined by the formula
      </p>
      <p>M    3: ( )  0 .</p>
      <p>
        Note that the set (
        <xref ref-type="bibr" rid="ref15">15</xref>
        ) is nonempty, since the vectors   3 in the case  2  0 and for   1 ,
9
 2  
      </p>
      <p>3</p>
      <p>
        For the set (
        <xref ref-type="bibr" rid="ref15">15</xref>
        ), let KM is the class of functions which can be represented as a finite sum of
quasipolynomials of the form (
        <xref ref-type="bibr" rid="ref14">14</xref>
        ) that differ from each other by different vectors  . So, KM is the
class of quasipolynomials of the variables x1, x2 , x3 and the zero quasipolynomial belongs to KM .
      </p>
      <p>
        Let the right-hand sides of conditions (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ), namely the functions f0 (x), f1(x), f2 (x) belong to the
class KM . Then there is an unique solution of problem (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ), (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ) in the class of quasipolynomials of
variables t, x1, x2 , x3 which belong to KM for each fixed t . This solution can be represented by the
formula
      </p>
      <p>2
u(t, x)   fk   k (t, ) ex 
k0
 O
,
where   x  1x1  2 x2  3x3 , O  (0,0,0) ,   (1 ,2 ,3 ) .</p>
      <p>
        The differential expressions f0  , f1   , f2   are obtained from the functions f0 (x) ,
f1(x) , f2 (x) by replacing the vector x by vector-derivative  . For each summand of the form (
        <xref ref-type="bibr" rid="ref14">14</xref>
        )
in the quasipolynomials f0 (x) , f1(x) , f2 (x) we put in correspondence the differential expression
Q( ) e11  22 33 , which acts on the function k (t, ) ex by formula
      </p>
      <p>Q( ) e11  22 33  k (t, ) ex </p>
      <p>
         Q( ) k (t, ) ex 
 O
 e xQ(x   )k (t, )
 
 
,
that is, the differential polynomial Q( ) acts onto the function k (t, ) ex , then we set the
vectorparameter  equals to   ( 1, 2 , 3) . If among the functions f0 (x) , f1(x) , f2 (x) is zero, then the
corresponding summand in formula (
        <xref ref-type="bibr" rid="ref16">16</xref>
        ) is zero. Therefore, formula (
        <xref ref-type="bibr" rid="ref16">16</xref>
        ) for finding the solution of
problem (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ), (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ) assumes the implementation of a finite number of differentiation of functions
0 (t, ), 1(t, ) , 2 (t, ) by parameters 1,2 ,3 .
      </p>
      <p>
        The fact that function (
        <xref ref-type="bibr" rid="ref16">16</xref>
        ) is the solution of problem (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ), (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ) follows from the commutativity of
the differentiation operators t ,  x ,  , taking into account that the functions 0 (t, ) , 1(t, ) ,
2 (t, ) satisfy equations (
        <xref ref-type="bibr" rid="ref4">4</xref>
        ) and conditions (
        <xref ref-type="bibr" rid="ref7">7</xref>
        ).
      </p>
      <p>
        The fact that the found solution of three-point problem (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ), (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ) is unique in the specified class of
quasipolynomials can be proved by contradiction method (see, for example, [23]). The choice of
quasipolynomials f0 (x) , f1(x) , f2 (x) exactly from the class KM is significant.
      </p>
      <p>
        Thus, if the functions f0 (x), f1(x), f2 (x) in conditions (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ) belong to the set KM , then
quasipolynomial solutions of problem (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ), (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ) are constructed by formula (
        <xref ref-type="bibr" rid="ref16">16</xref>
        ).
      </p>
      <p>Note that numerous studies have been devoted to the construction of quasipolynomial solutions of
partial differential equations and boundary value problems for these equations [27–31].</p>
      <p>
        Main result. The process of propagation of an ultrasonic wave in a relax medium with given wave
profiles at three time points is modeled by problem (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ), (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ) for the hyperbolic partial differential
(
        <xref ref-type="bibr" rid="ref14">14</xref>
        )
(
        <xref ref-type="bibr" rid="ref15">15</xref>
        )
(
        <xref ref-type="bibr" rid="ref16">16</xref>
        )
equation of the third order in time (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ) with three-point time conditions (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ). The method of
constructing the solution of problem (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ), (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ) is proposed. The class of quasipolynomials as a class of
uniqueness solvability of problem (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ), (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ) is indicated. Equation (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ) belongs to the important partial
differential equations which are used in the problems of ultrasound diagnostics.
3. The examples of application of the method to constructing solution of the
problem with given profiles of the ultrasonic wave at three moments of
time
      </p>
      <p>
        Let us investigate the process of acoustic oscillations for specifically given right-hand sides of
three-point conditions and parameters of the differential equation. We use the method which is
proposed in the previous section to construct the solution of problem (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ), (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ).
      </p>
      <p>
        Example 1. Let us consider problem (
        <xref ref-type="bibr" rid="ref2">2</xref>
        ), (
        <xref ref-type="bibr" rid="ref3">3</xref>
        ) for h  1 , f0 (x)  x12 , f1(x)  x2 , f2 (x)  2 . The
functions f0 (x) , f1(x) , f2 (x) are polynomials, therefore they have the form (
        <xref ref-type="bibr" rid="ref14">14</xref>
        ) and   O . Since
(O)  1  e1 2  0 , then these functions belong to KM . So, the unique solution of the problem
exists in indicated above class of quasipolynomials (in particular, in a subclass of polynomials). The
solution we can find by formula (
        <xref ref-type="bibr" rid="ref16">16</xref>
        ):
u(t, x)  2 0 (t, ) ex
1
  1(t, ) ex
2
 22 (t, ) ex
 O
Therefore,
u(t, x)  21 0 (t, )
      </p>
      <p> O
In formula (17), the function  (t)  21 0 (t, )
 O
nonhomogeneous ordinary differential equation
is the solution of three-point problem for
.
.</p>
      <p>(17)
 O
 O
 210 (t, )</p>
      <p> 2x110 (t, )
x21(t,O)  2 1(t, )</p>
      <p> O
 x2
2et  2  (1  e2 ) t
(1  e1)2
 0  2
 O
 x120 (t,O)
 O
 22 (t,O)</p>
      <p> 0  x12 et  e1(2  e1)  e1(1  e1) t
 x12 et  e1(2  e1)  e1(1  e1) t</p>
      <p>(1  e1)2
 x2
2et  2  (1  e2 ) t</p>
      <p>et 1  (1  e1) t
 2
(1  e1)2</p>
      <p>(1  e1)2
dt3  dt2  (t)  2dt  0 (t,O) ,</p>
      <p> (0)  (h)  (2h)  0 .</p>
      <p> (t)  c1 et 1  c2t  Atet  Bt3  Ct 2 ,</p>
      <p>
        This function is obtained by differentiating the problem (
        <xref ref-type="bibr" rid="ref4">4</xref>
        ), (
        <xref ref-type="bibr" rid="ref5">5</xref>
        ) for 0 (t, ) by the parameter 1
at the point   O . Calculations show that the function  (t) is a quasipolynomial of the form
where
      </p>
      <p>A 
2(1  )e2
(e 1)2
, B </p>
      <p>, C 
 e
3(e 1)
e 1  3e  2</p>
      <p>(e 1)2
nondegenerate system of algebraic equations
constants
c1
and
c2
satisfy
a</p>
      <p>
        ,
  3i(
        <xref ref-type="bibr" rid="ref1 ref1 ref1">1,1,1</xref>
        )
where
 1  3 t  1 t2  e13t .
      </p>
      <p>
         2 2 
Finally, we obtain the following solution of the problem
u(t, x)   1  3 t  1 t 2  e x1x23x3t  e
 2 4 4 
x1x2x3t 
3


 0 (t, )    3i(
        <xref ref-type="bibr" rid="ref1 ref1 ref1">1,1,1</xref>
        )   0 (t, ) 
  3i(
        <xref ref-type="bibr" rid="ref1 ref1 ref1">1,1,1</xref>
        )
planes x1  x2  x3  3  0 of the space
 1  3 t  1 t 2  e13t cos x1  x2  x3 .
      </p>
      <p> 2 2  3
For graphically illustrating the process of acoustic oscillations, we consider the solution on parallel
3 , where   , 3  is the distance from the origin of
coordinates to the plane.</p>
      <p>The solution of problem in variables t and  is 2 -periodical function by  and has the such
analytical factorized form</p>
      <p>2
The graph of function (18) of two variables t and  is depicted in Figure 2.</p>
      <p>u(t, ) 
(t 1)(t  2) 1t
e 3 cos .</p>
      <p>(18)
Figure: 2. Graphical dependence of the solution u(t, ) on time t and distance  .</p>
      <p>Therefore, function (18) describes the periodic oscillations of the ultrasonic wave with the period
T  2 by the variable  . The amplitudes of these oscillations for   0 and   3 are determined
by the corresponding formulas</p>
      <p>A1(t)  1 32 t  12 t2 e13t , A2 (t)  12 1 23 t  12 t2 e13t .</p>
      <p>These amplitudes are depicted in Figure 3 by a top and bottom lines.</p>
      <p>As noted above, the found solution is unique in the class of quasipolynomials which for the fixed
t belong to KM .</p>
      <p>Note that the ultrasonic wave oscillates in a limited range at arbitrary time moment and goes
exponentially to zero for t   on planes which are parallel to the plane x1  x2  x3  0 .</p>
    </sec>
    <sec id="sec-2">
      <title>4. Conclusions</title>
      <p>The mathematical model of the process of ultrasonic wave propagation in a relaxation medium
under the condition of setting the wave profile at three time points is investigated. The model is
reduced to a problem with three-point time conditions for a hyperbolic partial differential equation of
the third order.</p>
      <p>The class of quasipolynomials as a class of uniqueness solvability of the problem is established
and a practically effective method of constructing the solution in this class is proposed. The examples
of application of the specified technique are given.</p>
      <p>The proposed method is important in mathematical modeling of acoustic oscillatory processes in
relaxation environments. The results of the research can be used in medicine, in particular, in the
theory of ultrasound diagnostics.</p>
    </sec>
    <sec id="sec-3">
      <title>5. References</title>
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Three-Point Problem for Partial Differential Equation in a Two-Dimensional Domain, Journ.</p>
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